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saveliy_v [14]
2 years ago
10

Hello there, how are you? how’d you sleep? You look amazing today if i might add.

Mathematics
1 answer:
Zolol [24]2 years ago
6 0
I’m good how are you gorgeous!! :)
You might be interested in
Please help me with the question below
nata0808 [166]

Answer:

4

Step-by-step explanation:

If Judge is x years old and Eden is 6 years older, then Eden is x + 6 years old.

The second part tells us that Eden will be twice as old as Judge in two years.

This means that in two years: (Eden's age) = 2 * (Judge's age).

Since we know that Eden's age can be represented as x + 6 and Judge's age can be represented as x, we can write this: x + 6 = 2 * x

Simplify the equation:

x + 6 = 2x

6 = x = Judge's age (in two years)

If Judge is 6 two years later, then he must be 4 now.

To check our work, we can just look at the problem. Judge is 4 years old and Eden is 6 years older than Judge (that means Eden is 10 right now). Two years later, Eden is 12 and Judge is 6, so Eden is twice as old as Judge. The answer is correct.

6 0
3 years ago
What is 20% of $45.00?
Gnoma [55]
It is 9$ :)

45*0,2=9

YW
4 0
3 years ago
Read 2 more answers
HELP NEEDED ASAP! Thanks :)
Arlecino [84]

Answer:

3

Step-by-step explanation:

First we must find the total boxes of pens

15 + 9 = 24

Then we can divide the total cost by the total number of boxes of pens

$72 / 24 boxes = 3

4 0
2 years ago
One serving of rice has 44.9 grams of carbohydrates how many grams of carbohydrates de 2.5 servings of rice have
Fofino [41]

Answer:

112.25\ grams\ of\ carbohydrates    

Step-by-step explanation:

we know that

using proportion

\frac{1}{44.9}\frac{serving\ of\ rice}{grams\ of\ carbohydrates} =\frac{2.5}{x}\frac{serving\ of\ rice}{grams\ of\ carbohydrates} \\ \\x=44.9*2.5\\ \\x=112.25\ grams\ of\ carbohydrates

4 0
3 years ago
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
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