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JulsSmile [24]
3 years ago
10

Pls answer question below.

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
The answer your looking for is Flase
Alla [95]3 years ago
3 0

Answer:

false

Step-by-step explanation:

2^5 would be 2 x 2 x 2 x 2 x 2  not 2 x 5

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A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measurin
Ratling [72]

Answer:

The standard deviation of weight for this species of cockroaches is 4.62.

Step-by-step explanation:

Given : A different species of cockroach has weights that are approximately Normally distributed with a mean of 50 grams. After measuring the weights of many of these cockroaches, a lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

To find : What is the approximate standard deviation of weight for this species of cockroaches?

Solution :

We have given,

Mean \mu=50

The sample mean x=55

A lab assistant reports that 14% of the cockroaches weigh more than 55 grams.

i.e. P(X>55)=14%=0.14

The total probability needs to sum up to 1,

P(X\leq 55)=1-P(X>55)

P(X\leq 55)=1-0.14

P(X\leq 55)=0.86

The z-score value of 0.86 using z-score table is z=1.08.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

Where, \sigma is standard deviation

Substitute the values,

z=\frac{x-\mu}{\sigma}

1.08=\frac{55-50}{\sigma}

1.08=\frac{5}{\sigma}

\sigma=\frac{5}{1.08}

\sigma=4.62

The standard deviation of weight for this species of cockroaches is 4.62.

4 0
3 years ago
Select all of the following tables which represent y as a function of x.x 5 10 11y 3 9 15x 5 10 11y 3 9 9x 5 10 10y 3 9 15
11Alexandr11 [23.1K]

Answer:

Table 1 and 2 represent a function

Step-by-step explanation:

Given

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

<em>Table 2</em>

x 5 10 11

y 3 9 9

<em>Table 3</em>

x 5 10 10

y 3 9 15

Required

Determine which of the tables represent that y is a function of x

For a relation to be a function; the x values must be unique.

In other words, each x value must not be repeated;

Having said that;

Analyzing Table 1

<em>Table 1</em>

x 5 10 11

y 3 9 15

<em></em>

Note that the x rows are unique as no value were repeated;

Hence, Table 1 is a function

<em>Table 2</em>

x 5 10 11

y 3 9 9

Note that the x rows are unique as no value were repeated;

Hence, Table 2 is a function

<em>Table 3</em>

x 5 10 10

y 3 9 15

Note that the x rows are not unique because 10 was repeated twice;

Hence, Table 3 is not a function

7 0
3 years ago
Same this for me but 6,912 and 288 please help
Svetllana [295]

Answer:

what is the question

Step-by-step explanation:

Questions for answers

4 0
4 years ago
It is a linear equation but i don't know how to set the equation up , need help​
ryzh [129]

Step-by-step explanation:

x = number of novels

y = number of dictionaries

x = 8y

88x + 208y = 13680

now, using the identity of the first equation in the second equation gives us

88(8y) + 208y = 13680

704y + 208y = 13680

912y = 13680

y = 13680/912 = 15

x = 8y = 8×15 = 120

so, there were 120 novels and 15 dictionaries sold.

7 0
3 years ago
3/7•d=9/14 in this<br> Problem you want to find what d equals
sertanlavr [38]
<u>→ Chapter : Fractions ←</u>
<u><em>≡ We know that:</em></u>
⇔ (\frac{a}{b}) \div (\frac{c}{d})=(\frac{a}{b}) \times (\frac{d}{c})

<u><em>≡ Solution:</em></u>
⇒ (\frac{3}{7}) \times (d)=\frac{9}{14}
⇒ d=(\frac{9}{14}) \div (\frac{3}{7})
⇒ d=(\frac{9}{14}) \times (\frac{7}{3})
∴ \boxed{\frac{3}{2}}
7 0
3 years ago
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