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Aleonysh [2.5K]
3 years ago
7

HELP ME WITH THE EXERCISES PLEAASE

Mathematics
1 answer:
Zinaida [17]3 years ago
6 0
1.

1=87 corresponding angle.
2=180-87=93


2.

1=78 corresponding angles
2=78 verticle angles


3.

Set it up as (6x - 11) = 37
37 + 11 =48

6x = 48

x = 8


4.

Take 142 and see that it is supplementary to angle 2 so 180-142 = 38

38 is corresponding to the equation 2(x + 9)

So 2(x + 9) =38
Distributive property

2x + 18 = 38
38-18=20

2x =20

x = 10

Angle 2 is equal to 38 from supplementary to 142


I’m pretty positive about 1-3 but 4 maybe not be correct. But most likely these are correct
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469 iPads were donated.

Step-by-step explanation:

The school purchased 396 iPads in total: 300+96

Now, you subtract how many the school purchased from the total amount of iPads to see how many iPads were donated: 865-396 = 469

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Answer:

(x + 9) (x - 8)

Replace a with 9

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Step-by-step explanation:

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when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
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Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

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2 years ago
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