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Aleonysh [2.5K]
3 years ago
7

HELP ME WITH THE EXERCISES PLEAASE

Mathematics
1 answer:
Zinaida [17]3 years ago
6 0
1.

1=87 corresponding angle.
2=180-87=93


2.

1=78 corresponding angles
2=78 verticle angles


3.

Set it up as (6x - 11) = 37
37 + 11 =48

6x = 48

x = 8


4.

Take 142 and see that it is supplementary to angle 2 so 180-142 = 38

38 is corresponding to the equation 2(x + 9)

So 2(x + 9) =38
Distributive property

2x + 18 = 38
38-18=20

2x =20

x = 10

Angle 2 is equal to 38 from supplementary to 142


I’m pretty positive about 1-3 but 4 maybe not be correct. But most likely these are correct
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How to write into fractional expanded form 65.43
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Answer:

6543/100

Step-by-step explanation:

Multiply both numerator and denominator by 10 for every number after the decimal point

65.43 × 100

1 × 100

=

6543

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The sum of two numbers is 23. The sum of the smaller and 2 times the larger is 36. Find the numbers.
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What is the shortest distance Jill can travel is she leaves her house, goes to City Hall, to the Post Office, and then returns h
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28 miles

Step-by-step explanation:

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D) equilateral
maksim [4K]

Answer:

The length of side JK  is 4.7 units.

Step-by-step explanation:

Given:

Δ JKL is an Isosceles Triangle.

JL = 5x - 0.2

KL = x + 3.2

JK = 4x - 1.3

To Find:

The length of side JK = ?

Solution:

Δ JKL is an Isosceles Triangle. ......Given

JK = KL  .........................Given

Substituting the given values we get

4x-1.3=x+3.2\\\\4x-x=3.2+1.3\\\\3x=4.5\\\\x=\frac{4.5}{3} \\\\x=1.5

Now substituting 'x' in JK we get

l(JK)=4(1.5)-1.3\\\\\therefore l(JK)=4.7\ units

The length of side JK  is 4.7 units.

6 0
4 years ago
One month, Kcee worked 6 hours more than Alberto, and Atiana worked 4 times as many hours as Kcee. Together they worked 126 hour
alina1380 [7]

Answer:

no of hours worked by Kcee =  16 hours

no. of hours worked by Kcee = 22

no. of hours worked by Atiana =  88

Step-by-step explanation:

Let the no. of hours worked by Alberto be x

given that

Kcee worked 6 hours more than Alberto

no. of hours worked by Kcee = x + 6

Given

Atiana worked 4 times as many hours as Kcee

no. of hours worked by Atiana = 4*no. of hours worked by Kcee

no. of hours worked by Atiana = 4*(x + 6) = 4x + 24

Total hours worked by them together in terms of x = x + x + 6 + 4x + 24

Total hours worked by them together in terms of x = 6x + 30

As given Together they worked 126 hours

6x + 30 = 126 hours

6x = 126 - 30

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x = 16

Thus, no of hours worked by Kcee = x = 16 hours

no. of hours worked by Kcee = x + 6 = 16 + 6 = 22

no. of hours worked by Atiana =  4x + 24 = 4*16 + 24 = 64 + 24 = 88

3 0
3 years ago
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