To solve for this, we need to use Pythagorean Theorum.
Pythagorean Theorum is when we add the squares of the legs (A & B) to solve for the hypotenuse (C) or the side that's across from the 90 degree angle.
The formula for Pythagorean Theorum is A^2 + B^2 = C^2.
We have our two leg lengths, 15 and 36 (A & B).
Square 15 and 36.
15^2 = 225
36^2 = 1,296
Now that we have our side lengths, let's add them up.
225 + 1,296 = 1,521.
Now, to solve for C, we need to square root our sum.
The square root of 1,521 is 39.
Your hypotenuse is 39.
Your answer is C.) 39.
I hope this helps!
mode = 43
the mode is the value which occurs most
43 occurs 3 times, 38 twice and the others only once
Hence 43 is the mode
Answer:
the water to be added is 0.2 L
Step-by-step explanation:
The computation of the water to be added is given below:
The banberry amount is
= 7% of 6 Liters
= 0. 42L
Now
Let us assume the amount of water added be x L
So, the total solution is
= 6+ x L
Now percentage of banberry is
= 0.42 × 100 ÷ (6+x)
5 = 0.42 × 100 ÷ (9 + x)
9 + x = 9.2
x = 0.2 L
hence, the water to be added is 0.2 L
Answer:
1240 (I'm not so sure but per my calculation that is what i got)
Step-by-step explanation:
Boy : Girl
11 : 9
124 + x : x
11/9 = 124 + x / x
9(124 + x) = 11 x
1116 + 9x = 11x
1116 = 11x - 9x
1116 = 2x
x = 558
Thus, there are 558 girls in the school
Number of boys = 124 + x
= 124 + 558
= 682
Therefore, total number of students = 558 + 682 = 1240 students
Answer:
It is expected that linearization beyond age 20 will be use a function whose slope is monotonously decreasing.
Step-by-step explanation:
The linearization of the data by first order polynomials may be reasonable for the set of values of age between ages from 5 to 15 years, but it is inadequate beyond, since the fourth point, located at 
, in growing at a lower slope. It is expected that function will be monotonously decreasing and we need to use models alternative to first order polynomials as either second order polynomic models or exponential models.
