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11111nata11111 [884]
3 years ago
11

In parallelogram QRST, diagonals QS and RT intersect at point E. Which statement must be true? QS ⊥ RT ΔRES ≅ ΔTEQ ∠RQS ≅ ∠SQT Δ

TQE ≅ ΔRQE
Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

ΔRES ≅ ΔTEQ

Step-by-step explanation:

A parallelogram is a quadrilateral (has four sides and four angles) in which opposite sides are equal and parallel to each other.

Opposite angles of a parallelogram are equal and the diagonals bisect each other. Each diagonal of a parallelogram separates it into two congruent triangles.

Given parallelogram QRST with diagonals QS and RT intersecting at point E

Therefore, the diagonals divide parallelogram QRST into congruent triangles, hence:

ΔRES ≅ ΔTEQ

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Two basketballs are thrown along different paths. Determine if the basketballs’ paths are parallel to each
Paul [167]

Answer:

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

Step-by-step explanation:

Remember that:

  • Two lines are parallel if their slopes are equivalent.
  • Two lines are perpendicular if their slopes are negative reciprocals of each other.
  • And two lines are neither if neither of the two cases above apply.

So, let's find the slope of each equation.

The first basketball is modeled by:

\displaystyle 3x+4y=12

We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:

4y=-3x+12

And divide both sides by four:

\displaystyle y=-\frac{3}{4}x+3

So, the slope of the first basketball is -3/4.

The second basketball is modeled by:

-6x-8y=24

Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:

-8y=6x+24

And divide both sides by negative eight:

\displaystyle y=-\frac{3}{4}x-3

So, the slope of the second basketball is also -3/4.

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

3 0
3 years ago
Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
Triss [41]

Answer:

By definition, the derivative of f(x) is

lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Let's use the definition for f(x)=\frac{1}{x}

lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}

Then, f'(x)=\frac{-1}{x^2}

7 0
3 years ago
What is the area of this composite shape
makvit [3.9K]

Answer:

51in

Step-by-step explanation:

you first have to find the area of the square by multiplying 6 and 7 which is 42. Then you have to find area of the triangle and the formula to do that is (length×width)÷2 . to find the length you have to subtract 7 from 13 which is 6 and the length you have to do 6-3 which is 3 then (6×3)÷2=9 and then you add the area of the square and the area of the triangle and get 42+9=51

6 0
4 years ago
over six games, a hockey team scored 18 goals. On average, how many goals did the team score each game
Ede4ka [16]

Answer:

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Step-by-step explanation:

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Average = 18/6

Average = 3

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4 years ago
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cricket20 [7]
Here is the method for solving that equation:

Step #1:  Write the equation:

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Step #2:  Divide each side of the equation by -15 :

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