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11111nata11111 [884]
3 years ago
11

In parallelogram QRST, diagonals QS and RT intersect at point E. Which statement must be true? QS ⊥ RT ΔRES ≅ ΔTEQ ∠RQS ≅ ∠SQT Δ

TQE ≅ ΔRQE
Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

ΔRES ≅ ΔTEQ

Step-by-step explanation:

A parallelogram is a quadrilateral (has four sides and four angles) in which opposite sides are equal and parallel to each other.

Opposite angles of a parallelogram are equal and the diagonals bisect each other. Each diagonal of a parallelogram separates it into two congruent triangles.

Given parallelogram QRST with diagonals QS and RT intersecting at point E

Therefore, the diagonals divide parallelogram QRST into congruent triangles, hence:

ΔRES ≅ ΔTEQ

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VashaNatasha [74]

The chart does not represent a linear quantity

<h3>How to determine if there are linear quantities in the chart shown?</h3>

From the chart, we have the following coordinates

(x, y) = (0.10, 0.14), (0.50, 0.32), (1.00, 0.46), (1.70, 0.59) and (2.00, 0.63)

To determine if the chart is a linear quantity, we simply calculate the slope using the coordinates.

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

So, we have:

m = (0.32 - 0.14)/(0.50 - 0.10) = 0.45

m = (0.46 - 0.32)/(1.00 - 0.50) = 0.28

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Read more about linear equations at:

brainly.com/question/1884491

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2 years ago
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3 years ago
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