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11111nata11111 [884]
3 years ago
11

In parallelogram QRST, diagonals QS and RT intersect at point E. Which statement must be true? QS ⊥ RT ΔRES ≅ ΔTEQ ∠RQS ≅ ∠SQT Δ

TQE ≅ ΔRQE
Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

ΔRES ≅ ΔTEQ

Step-by-step explanation:

A parallelogram is a quadrilateral (has four sides and four angles) in which opposite sides are equal and parallel to each other.

Opposite angles of a parallelogram are equal and the diagonals bisect each other. Each diagonal of a parallelogram separates it into two congruent triangles.

Given parallelogram QRST with diagonals QS and RT intersecting at point E

Therefore, the diagonals divide parallelogram QRST into congruent triangles, hence:

ΔRES ≅ ΔTEQ

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the areas of the world's oceans are listed in the table order the oceans according to their area from least to greatest.
agasfer [191]
Pacific ocean is the biggest ocean
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3 years ago
Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s
lakkis [162]

Answer:

<u>P (E1) = 1/2 or 50%</u>

<u>P (E2) = 3/13 or 23%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2.  Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

8 0
3 years ago
Read 3 more answers
Answer number one please
tankabanditka [31]

Answer:

-3 + 6 = -3

Step-by-step explanation:

add the terms -3 and 6

exponent law

6 0
3 years ago
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Which equation can be simplified to find the inverse of y = 5x2 + 10?
zmey [24]

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

Step-by-step explanation:

interchanging the variables

x = 5y^2 + 10

5y^2 +10 = x

5y^2 = x - 10

dividing by 5

5y^2/5 = x/5 + -10/5

y^2 = x/5 + - 10/5

y^2 = x/5 - 2

y = 5 (x-10) 0/5 (sq.rt)

g(5x^2 + 10) = 5x/5

g(5x^2 + 10) = x

f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10

5 0
3 years ago
Read 2 more answers
Kindly Only Answer if you know how to do this problem:
steposvetlana [31]
Its representedf by 2 polygons(triangles)
first one :
24-20=4
11-6=5
second:
24-14=10
11-7=4
B. frind area of 2 small trianges
a=(base x height )/2
first=4x5/2=10ft   square
second=10x 4/2=20ft square
add them=10+20=30
rectangle24x 11=264
264-30=234
7 0
3 years ago
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