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Elenna [48]
3 years ago
7

Edith wants to make a paperweight at pottery class. She wants the paperweight to have a pyramid-like shape with a base area of 1

20 square centimeters, and she wants it to weigh 400 grams. The density of the clay she is using is 1.61 grams per cubic centimeter. What should be the height of the paperweight?
Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

6.25

Step-by-step explanation:

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Leah's parents are planning to give her a gift and want to wrap it first. The gift is in a rectangular box with a height of 3 in
jekas [21]
128 square inches of wrapping paper, since the width would be the Z Axis, That would make a Square 3X4= 12, 12X2= 24. 3X7= 21X4= 104, 104+24=128? That's what I figured. Can you send me a photo of the problem?
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3 years ago
The scale drawing represents Kim’s living room. She wants to put new baseboards on the walls of the room. If the scale is 2 cm:1
Serga [27]
The answer is B, because if you draw the baseboards on the scale drawing, you'll get nineteen baseboards. 19 x 4,19 = 79,61

5 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
Complete the explanation on the 2 errors Margaret made, and then give the correct answer.
klemol [59]

Answer:

For the first page 2nd line they did 88846 squared instead of cubed.

The correct answer is 935,087,000,000,000.

Step-by-step explanation:

8 0
2 years ago
Sam and Avery are making small and large birdhouses for an upcoming craft show. They will sell the small birdhouses for $10 and
kupik [55]

Answer:

<h2>They should make 8 small ones and 12 large ones.</h2><h2>$260 they will make in total.</h2>

Step-by-step explanation:

They want to make as much money as possible.

Small bird house gives them $10 and large birdhouse give them $15.

Avery has time to decorate 12 birdhouse of either size.

Hence, to maximize the earning, Avery should build 12 large ones.

Sam can make any of the combination below in 24 hours.

4 Large and 1 small bird house, which will make 4 \times 15 + 10 = 70

3 Large and 3 small bird house, which will make 3 \times15 + 3 \times10 = 75

2 Large and 4 small bird house, it will gain 2 \times15 + 4 \times10 = 70

1 Large and 6 small bird house, it will make 1 \times15 + 6 \times10 = 75

8 small bird house, which will gain 8\times10 = 80

The profit will be maximize if Sam build 8 small bird houses.

Thus, they will make 80 + 12\times15 = 260.

5 0
3 years ago
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