The angle m∠AFE is 128 degrees.
<h3>How to find angles?</h3>
∠AFB ≅ ∠EFD
∠EFD = 5x + 6
m∠DFC = (19x - 15)°
m∠EFC = (17x + 19)°
m∠AFE = ?
m∠AFB + m ∠EFD + m∠AFE = 180
Therefore,
5x + 6 + 5x + 6 + m∠AFE = 180
5x + 5x + 6 + 6 + m∠AFE = 180
10x + 12 + m∠AFE = 180
10x + m∠AFE = 180 - 12
10x + m∠AFE = 168
m∠AFE = 168 - 10x
m∠EFC = m ∠EFD + m∠DFC
17x + 19 = 5x + 6 + 19x - 15
17x - 5x - 19x = 6 - 15 - 19
-7x = - 28
x = 28 / 7
x = 4
Therefore,
m∠AFE = 168 - 10x
m∠AFE = 168 - 10(4)
m∠AFE = 168 - 40
m∠AFE = 128°
Therefore, the angle m∠AFE = 128°
learn more on angles here: brainly.com/question/13212279
#SPJ1
Answer:
Therefore,
Step-by-step explanation:
Given:
![A=\left[\begin{array}{ccc}3&6&9\\2&4&8\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%266%269%5C%5C2%264%268%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To Find:
a₂₁ = ?
Solution:
Let,
![A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B11%7D%26a_%7B12%7D%26a_%7B13%7D%5C%5Ca_%7B21%7D%26a_%7B22%7D%26a_%7B23%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
We require ' a₂₁ ' i.e Second Row First Column Element
So on Comparing we get
∴
Therefore,
Answer:
f(x)-3x+5 and g(x)=4+5 is it true ?Step-by-step explanation:
