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Yuri [45]
3 years ago
14

If a 10-pound sack of potatoes costs $6.55, how much would 1 pound cost? Round your answer to the nearest cent.

Mathematics
1 answer:
lozanna [386]3 years ago
8 0
Hello there!

6.55 ÷ 10 = .655

1 pound would cost about $0.65
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HELP WILL GIV YOU 30 POINTS BUT HELP ME
MrRa [10]

Answer:

3/4

Step-by-step explanation:

Constant of Proportionality is just a fancy way of saying slope (for a line passing through (0, 0), at least).

You can find it by looking at y/x, which will be equal at any point on the line (which is why it is a "constant").

So, for multiple points on the line:

1.5 / 2 = 3/4

3 / 4 = 3/4

4.5 / 6 = 3/4

8 0
3 years ago
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kari74 [83]

Answer:

1)6cm²

2)2

3)1000cm²

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3 years ago
PLEASE HELP WILL MARK BRAINLIEST
Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

7 0
3 years ago
Read the image for instructions
Gwar [14]

Answer:

4 ther are 4 line symmetery

8 0
2 years ago
Read 2 more answers
AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear
VMariaS [17]

Answer:

\overline{QT}

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides A(x_1,y_1) and B(x_2,y_2) in the ratio m:n=3:2

The x-coordinate is given by:

x=\frac{mx_2+nx_1}{m+n}

The y-coordinate is given by:

y=\frac{my_2+ny_1}{m+n}

AB has coordinates A(-5,9) and B(7,- 7)

We substitute the values to get:

x=\frac{3*7+2*-5}{3+2}

x=\frac{21-10}{5}

x=\frac{11}{5}

and

y=\frac{3*-7+2*9}{3+2}

y=\frac{-21+18}{5}

y=-\frac{3}{5}

Therefore C has coordinates  (\frac{11}{5},-\frac{3}{5})

The line segment that contains C is \overline{QT}

See attachment.

6 0
3 years ago
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