2 your welcome d d d d d d. d d d d s s s s
Your answer is Y= -x\5+7\15
Answer:
a) h(t) = -16t² + 56t; b) the graph is attached; c) maximum height is 49 feet, it takes 1.75 seconds to reach the maximum, and it is in the air for 3.5 seconds.
Step-by-step explanation:
Equations for these situations are in the form
h(t) = -16t² + v₀t + h₀, where t is the tie in seconds, v₀ is the initial velocity and h₀ is the initial height. The initial height in this case is 0, since it is launched from the ground; and the initial velocity is 56. This gives us the function
h(t) = -16t² + 56t
The graph is attached.
Using the graph, we can trace the function to the maximum. The y-value of the maximum, or the maximum height, is 49 feet. The x-value of the maximum, the time it takes, is 1.75 seconds.
The roots of this equation are at x = 0 and x = 3.5. This means the rocket is in the air for 3.5-0 = 3.5 seconds.
What is the first quartile of this data set? 10,11,12,15,17,19,22,24,29,33,38
puteri [66]
The first quartile is the middle of the first half.
Which would be the number 12 I think