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3 years ago

Please help! Quickly!

Mathematics

1 answer:

ss7ja [257]3 years ago

8 0

The last one is the last correct answer that needs to be checked!!

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I need help with this question. i keep having trouble

nignag [31]

Answer:

Step-by-step explanation:

The angles <JKL, <EKL, and <JKE form a full angle which means their sum is equal to 360:

134 + 21x + 6 + 5x = 360 add like terms

140 + 26x = 360 subtract 140 from both sides

26x = 220 divide both sides by 26

x = 8.4 approximately

to find the angle m<JKL replace x with the value we found.

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2 years ago

MATH

olchik [2.2K]

Answer:

f(-4) = -2

Step-by-step explanation:

To find f(-4) use the "piece" of the function rule defined for x < -3 (because -4 is less than -3). That part of the rule says the output (range) value is x + 2, so f(-4) = -4 + 2 = -2.

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2 years ago

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Jeremiah received $65 for his birthday and used part of it to buy 3 video games. The games cost the same amount, and he had $14

Dmitry_Shevchenko [17]

65-3x=14 is the algebraic equation

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3 years ago

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(Click the Picture for my question) and thank you!

ELEN [110]

The answer should be C

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3 years ago

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Your plan was to be on the road by 9 A.M. but you did not leave the garage until 10 A.M. You then drove with the cruise control

Wittaler [7]

Answer:

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

Step-by-step explanation:

The average speed is given by the following equation:

$v = \frac{d}{t}$

From 10A.M. to noon.

You traveled at 50mph during 2 hours. So how long you traveled?

$50 = \frac{d}{2}$

$d = 50*2$

$d = 100$

You traveled 100 miles.

What was your average speed over the time interval from 9 A.M. to noon

From 9 A.M. to 10 A.M, you did not travel.

From 10 P.M. to noon, 100 miles.

So 100 miles during 3 hours.

$v = \frac{d}{t} = \frac{100}{3} = 33.33$

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.

8 0

3 years ago