Exponentail thingies
easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0
now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero
5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1
5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4
x=log₅1 and/or log₅4
second quesiton
same thing
1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero
2^x-8=9
2^x=8
x=3
2^x-2=0
2^x=2
x=1
x=3 or 1
first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3
Answer:
1. a. z test for means and t test for means.
2. C. HA : mu1 - mu2 > 0
Step-by-step explanation:
Hypothesis testing is used in a situation where there are more than 1 alternative available. The t test is conducted in the mean which determines the t value and then this value is compared with p value to identify the situation whether to accept or reject the null hypothesis. The alternative hypothesis in this situation is is represented by mu.
<span>Subtract 13.09 from 21.59 giving you 8.5. Since the amount of space on both the left and right margin have to be equal you would divide by 2 to get 4.25 on the left margin as well as the right.</span>
Answer:
set X/Y = {0,23}
Step-by-step explanation:
We are given the sets;
X = {0, 12, 23}
Y = {3, 12, 15}
Now, we want to find the set X/Y.
The set X/Y means the set that has numbers which are only in set X but not in set Y.
The numbers from inspection of both sets are 0 and 23.
Thus;
set X/Y = {0,23}
Due that the artist needs 8 orange beads per each bracelet and he only have 15 beads of this color, he only could form 1 bracelet.
After finish the first bracelet, only left 7 orange beads (15 - 8), which are not enough for form another one.
