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SpyIntel [72]
2 years ago
10

Dina invests $600 for 5 years at a rate of 2% per year compound interest.

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0

Answer:

The investment after 5 years is $ 662.45.

Step-by-step explanation:

Principal, P = $ 600

Time, t = 5 years

Rate of interest, R = 2 %

Time , t = 5 years

The amount after the time 5 years is

A = P \times \left ( 1+\frac{R}{100} \right )^t\\\\A = 600\left ( 1+0.02 \right )^5\\\\A = 662.45

So, the investment after 5 years is $ 662.45.

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$25.98

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A plumbing company charges a $95 fee for each job, plus $65 foreach hour that the job lasts. The expression 65h + 95can be used
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Lucy Baker is analyzing demographic characteristics of two television programs: COPS (population 1) and 60 Minutes (population 2
drek231 [11]

Answer and Explanation:

Her alternative hypothesis is that there is some difference between the means of the ages of the audiences of the two television programs. That is, the mean ages of the two audiences are not the same.

If the mean of the ages of the audiences of television programme 1 (COPS) is xbar₁

And the mean of the ages of the audiences of the television programme 2 (60 minutes) is xbar₂

Her alternative hypothesis can be represented mathematically as

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7 0
3 years ago
Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the
Rama09 [41]

<em><u>Question:</u></em>

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s   2s   3s   4s

<em><u>Answer:</u></em>

It takes 2 seconds for object to hit the ground

<em><u>Solution:</u></em>

<em><u>The given equation is:</u></em>

h(t) = -16t^2 + v_0t+h_0

Initial velocity = 27 feet/sec

h_0 = 10\ feet

Therefore,

h(t) = -16t^2 +27t+10

At the point the object hits the ground, h(t) = 0

-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0

Solve by quadratic formula,

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0
3 years ago
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