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Tomtit [17]
3 years ago
6

The cost of 3 scarves is $26.25. What is the unit price? (cost per scarf)

Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0

$8.75 because 26.25 divided by 3 equals $8.75.

hope this helps

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X-2y=18 2x+y=6 parallel perpendicular or neither
sergey [27]
<h3>Therefore they are perpendicular.</h3>

Step-by-step explanation:

A equation of line is

y =mx +c

Here the slope of the line is m.

Given equations are

x - 2y = 18

⇔-2y = -x +18

\Leftrightarrow y =\frac{1}{2} x -9............(1)

and 2x + y = 6

⇔y = -2x +6 ............(2)

Therefore the slope of equation (1) is(m_1)= \frac{1}{2}

Therefore the slope of equation (2) is(m_2)= -2

If two lines are perpendicular, when we multiply their slope we get -1.

therefore,

m_1. m_2 =\frac{1}{2}. (-2) = -1

Therefore they are perpendicular.

4 0
3 years ago
PLEASE HELP due soon!I forgot how to do it omg
Flura [38]

Answer:

(3, -3) is correct

Step-by-step explanation:

-4 × 3 = -12. -12 + 9 = -3

8 0
3 years ago
A teacher buys a picture for the library. The teacher pays 10.5% sales tax on the original price of the picture. The original pr
lawyer [7]

Answer:$7.56 because 72 times 0.105 is 7.56

Step-by-step explanation:

3 0
3 years ago
A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on ea
weqwewe [10]

Answer:

a)  8*88*10⁻⁶ ( 0.00088 %)

b) 0.2137 (21.37%)

Step-by-step explanation:

if the test contains 25 questions and each questions is independent of the others, then the random variable X= answer "x" questions correctly , has a binomial probability distribution. Then

P(X=x)= n!/((n-x)!*x!)*p^x*(1-p)^(n-x)

where

n= total number of questions= 25

p= probability of getting a question right = 1/4

then

a) P(x=n) = p^n = (1/4)²⁵ = 8*88*10⁻⁶ ( 0.00088 %)

b) P(x<5)= F(5)

where F(x) is the cumulative binomial probability distribution- Then from tables

P(x<5)= F(5)= 0.2137 (21.37%)

7 0
4 years ago
Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
MAXImum [283]

Answer:

<h2>7</h2>

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

5 0
3 years ago
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