The answer is 6/5 (six over five) 100 divided by 20
Step-by-step explanation:
(a) dP/dt = kP (1 − P/L)
L is the carrying capacity (20 billion = 20,000 million).
Since P₀ is small compared to L, we can approximate the initial rate as:
(dP/dt)₀ ≈ kP₀
Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.
20 = k (6,100)
k = 1/305
dP/dt = 1/305 P (1 − (P/20,000))
(b) P(t) = 20,000 / (1 + Ce^(-t/305))
6,100 = 20,000 / (1 + C)
C = 2.279
P(t) = 20,000 / (1 + 2.279e^(-t/305))
P(10) = 20,000 / (1 + 2.279e^(-10/305))
P(10) = 6240 million
P(10) = 6.24 billion
This is less than the actual population of 6.9 billion.
(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))
P(100) = 7570 million = 7.57 billion
P(600) = 20,000 / (1 + 2.279e^(-600/305))
P(600) = 15170 million = 15.17 billion
Answer:
Step-by-step explanation:
Given
radius of wheel 
Time period of Wheel 
and
, where 

Let at any angle
with vertical position of a point is given by


and 
for velocity differentiate x and y to get


Height at any time t is given by

Answer:
6
Step-by-step explanation:
Area = 1/2( base times height)
since the height is perpendicular to the base
therefore
6 = 1/2(3) h
12 =3h
4=h
4 units away from the y=2 line is at the y coordinate of 6
Answer:
81/50
Step-by-step explanation:
=8/10+82/100
=8/10+41/50
=40+41/50
=81/50