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Complete Question
Write a rational equation that relates the desired percentage p, to the amount A of a 30% solution that needs to be added to 1 liter of 10% acid solution to make a blend that is p% acid, where 0<p<100 . What is a reasonable restriction on the set of possible values of ? Explain your answer.
Answer:
100(0.1 + 0.3A)= (1 + A) P
Step-by-step explanation:
A of a 30% solution that needs to be added to 1 liter of 10% acid solution to make a blend that is p% acid,
Hence,
10% of 1 + 30% of A = p%(1 + A)
0.10 + 0.3A = (p/100)(1 + A)
Divide both sides by 1 + A
0.1 + 0.3A/ 1 + A = p/100
Cross Multiply
100(0.1 + 0.3A) = 1 + A(p)
From the above calculation, we can see that, the blend that would be formed is not lower than 10% or greater than 30%
10% < p< 30%
Answer:
5.5
Step-by-step explanation:
8.25/3=2.75
2.75 times 2 is 5.5
Direct Proportion functions look like this:
y=kx
'k' is the constant of proportionality and in this case its 7.5 or 15/2.
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When x=1, y=7.5
When x=2, y=15
When x=3, y=22.5
Therefore y is directly proportional to x.
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DIRECT PROPORTION EXPLAINED:
Say a football costs £7.50. If you buy one football you'll have to pay out £7.50, but if you you buy two footballs you'll have to pay out £15.00. Therefore the cost of the football(s) is directly proportional to the amount of footballs you buy. C=cost, f=football(s) and C<span>∝f, therefore C=kf, but as k=7.5, C=7.5f.
INVERSE PROPORTION EXPLAINED:
If it were to take 8 hours for one bricklayer to set up a wall, how long would it take for two bricklayers to set up a wall? The answer in this case would be 4 hours.
T=time to set up a wall
b=bricklayer(s)
Therefore T</span><span>∝1/b, and T=k/b. In this case k=8 so T=8/b.
When b=1, T=8.
When b=2, T=4.
We'd say that the time it would take for bricklayers to set up a wall would be inversely proportional to the amount of bricklayers available.</span>
Answers:
- Incorrect
- Correct
- Correct
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Explanation:
When applying any kind of reflections, the parallel sides will stay parallel. Check out the diagram below for an example of this.
So PQ stays parallel to RS. Also, QR stays parallel to PS.
The statement "PQ is parallel to PS" is incorrect because the two segments intersect at point P. This letter "P" is found in "PQ" and "PS" to show the common point of intersection. Parallel lines never intersect.
