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3 years ago

The function of while loop is

Computers and Technology

1 answer:

Alona [7]3 years ago

4 0

Answer:

B repeat a chunk of code until the condition is true im 88% sure

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Analyze the error in the html code : HTML

Andrei [34K]

Answer:

The World Wide Web Consortium provide a simple online tool (https://validator.w3.org/) that automatically check your HTML code and point out any problems/errors your code might have, such as missing closing tags or missing quotes around attributes.

Explanation:

your question is not clear

hope it helps

6 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Write a program to find the product of 3 numbers

ziro4ka [17]

Answer:

#include<iostream>

using namespace std;

int main()

{

int a,b,c;

cout<<"enter the value of a:";

cin>>a;

cout<<"enter the value of b:";

cin>>b;

cout<<"enter the value of c:";

cin>>c;

cout<<"product is:"<<(a*b*c);

return 0;

}

Explanation:

6 0

3 years ago

Read 2 more answers

How do you adjust the shear of a shape?

Aloiza [94]

The answer is D. Appearance panel

7 0

4 years ago

Read 2 more answers

What is the numerical ratio that is equivalent to 19.2 dB?

mrs_skeptik [129]

Answer: 83.17

Explanation:

By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.

It applies specifically to power, and it is defined as follows:

P (dB) = 10 log₁₀ P₁ / P₂

Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.

In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.

Applying the dB definition, we can write the following:

10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92

Solving the logarithmic equation, we can compute X as follows:

X = 10^1.92 = 83.17

X = 83.17

4 0

3 years ago