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Anon25 [30]
3 years ago
5

PLEASE HELP!!! THIS IS DUE TODAY! WILL MARK BRAINLIEST!

Computers and Technology
1 answer:
8090 [49]3 years ago
7 0

Answer:

-be nice

-be respectfull

-dont bully

-if u see somthing say somethung

-dont use same password for everything

Explanation:

You might be interested in
Assure that major, minor, sub1 and sub2 each contain four digit numbersIf less than four digits are entered in major OR minor OR
Zigmanuir [339]

Answer:

import re

#section 1

while True:

   try:

       major=input('Enter Major: ')

       if re.search(r'^\d{1,4}$',major):

           minor=input('Enter minor: ')

       else:

           raise

       try:

           if re.search(r'^\d{1,4}$',minor):

               sub1=input('Enter sub1: ')

           else:

               raise

       

           try:

               if re.search(r'^\d{1,4}$',sub1):

                   sub2=input('Enter sub2: ')

               else:

                   raise

           

               try:

                   if re.search(r'^\d{1,4}$',sub2):

                       break

                   else:

                       raise

               except:

                   print('enter a correct sub 2')

           except:

               print('enter a correct sub1')        

       except:

           print('Enter a correct minor ')            

   except:

        print('enter a correct Major')

#section 2

sub1= f"{int(sub1):04d}"

sub2= f"{int(sub2):04d}"

major= f"{int(major):04d}"

minor= f"{int(minor):04d}"

if major == '0000' and minor == '0000' and sub1=='0000' and sub2=='0000':

   print('INVALID!!! Acount Number')

else:

   print('-----------------------')

   print('Your Account Number is')

   print(major, minor, sub1, sub2)

   print('-----------------------')

Explanation:

The programming language used is python 3

The Regular  Expression Module was imported to allow us perform special operations on string variables.

This is the pattern that was used to check if an input was valid or invalid re.search(r'^\d{1,4}$',string)

what this pattern does is that it ensures that:

  1. (\d) represents digits that is any number from 0-9.
  2. ( ^ ) ensures that it starts with a digit.
  3. ({1,4}) accepts digits with length ranging from 1-4. i.e you can enter at least one digit and at most four digits.
  4. ($) ensures that the input ends with a digit
  5. string is the text that is passed to the pattern

we also made use of fstrings

sub1= f"{int(sub1):04d}"

the above line of code takes 'sub1' in this case, and converts it temporarily to an integer and ensures it has a length of 4 by adding 0's in front of it to convert it to a four digit number.

These are the major though areas, but i'll explain the sections too.

#section 1

In this section the WHILE loop is used in conjunction with the TRY and EXCEPT block and the IF statement to ensure that the correct input is given.

The while loop will keep looping until the correct input is inserted  before it breaks and each input is tested in the try and except block using the if statement and the regular expression pattern I explained, as a result, you cannot input a letter, a blank space, a punctuation or numbers with length greater than 4, it has to be numbers within the range of 1-4.

#section 2

The second section converts each entry to a four digit number and checks with an if statement if the entry is all zeros (0000 0000 0000 0000) and prints invalid.

Otherwise, it prints the account number.

check the attachment to see how the script runs.

4 0
3 years ago
Convert (65.125)10 to octal.
grigory [225]

Answer:

101.1

Explanation:

Keep in mind that octal has 8 numbers

Step 1: Split your number in 2 parts (integer part and decimal part):

  • integer part 65
  • decimal part 0.125

Step 2: Convert the decimal part. For this step you need to multiply your decimal part and 8 (8 correspond the octal base) and get the integer part until you need it:

      0.125 * 8 =  1

So your decimal part correspond to number 1 in octal = (1)8

Step 3: Convert integer part: for this step you need to divide your integer part by 8 until you can and get the remainder

      65 / 8 = 8 remainder 1

        8 / 8 = 1 remainder 0

         1 / 8 = 0 remainder 1

Step 4: join the remainders from bottom to top and get the integer part

            101

Step 5: join the integer part and the decimal part to get the octal convertion

              101.1

5 0
3 years ago
Convert<br> 0.625 to binary
Anastaziya [24]

\huge{ \rm{Question:}}

Convert

0.625 to binary

\huge{ \rm{Answer:}}

Translate 0.625 into a fraction. We all know that 0.5 is ½. We know that the remainder, 0.125, is ⅛. Add them together, and you get ½ + ⅛ = ⅝.

Now, in binary, the positions to the right of the point are , which is ½, ¼, and ⅛ respectively.

⅝ is 5 × ⅛. 5 in binary is 101. So, ⅝ is

= 0.101

8 0
2 years ago
Match each definition to the correct type of media.
Murrr4er [49]

Answer:

1-2

2-3

3-1

Explanation:

I couldn't find a way to explain this.

6 0
2 years ago
Read 2 more answers
URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
2 years ago
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