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yawa3891 [41]
3 years ago
9

The sum of two numbers is 60. The greater number is 6 more than the smaller number. Which equation can be used to solve for the

smaller number?
1) x + (x + 6) = 60
2) x- (x + 6) = 60
3) x(x + 6) = 60
04) x(x-6) = 60​
Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0

Answer:

  • 1) x + (x + 6) = 60

Step-by-step explanation:

<u>Let the numbers be x and y</u>

  • x + y = 60
  • y = x + 6

<u>Then, substituting y:</u>

  • x + (x + 6) = 60

Correct option is 1)

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Answer:

it will be $1.50 (sure yan ah diyan joke)

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3 years ago
Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor
Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

the lengths of the sides of BRAD are:

\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}

The lengths of the sides of KELY are:

\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}

Each side of KELY is twice the length of the corresponding side on BRAD.  This makes the ratio of the sides 2:1 and the figures are similar.

8 0
3 years ago
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What is the simplified form of the expression? (m^-1m^5/m^-2)^-3
Eva8 [605]
1 (((m^(-1)) (m^5)) / (m^(-2)))^(-3) =1/m^18
5 0
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The distance between X and Y is 6 1/2 units. Which number could represent the point Y?
tiny-mole [99]

Answer:

\huge\boxed{\sf 3.5}

Step-by-step explanation:

Distance = \sf 6 \frac{1}{2} \ units = 6.5 \ units

Here X is -3

So,

Point Y = -3 + 6.5 = 3.5

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
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Point Q'Q ′ Q, prime is the image of Q(0,6)Q(0,6)Q, left parenthesis, 0, comma, 6, right parenthesis under the translation (x,y)
Marina86 [1]

Q is located at (0,6)

The translation rule is (x,y) \to (x+7,y-5) which says to add 7 to the x coordinate and subtract 5 from the y coordinate. Doing that to (0,6) moves it to (7,1) which is where point Q' is located.

In other words, if you shift point Q(0,6) seven units to the right and five units down, then it arrives at Q ' (7,1)

<h3>Answer: (7, 1)</h3>

8 0
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