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blsea [12.9K]
3 years ago
10

Look at the picture, I’ll give 40 points. If it’s correct

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0

Answer:

8

Step-by-step explanation:

I don't know how to explain

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What is the domain of the function f(x)=−4log2(x+3)−6 ? enter your answer in the box?
salantis [7]
Try this solution:
1. according to the definition of logarithm
log_ab=c \ =\ \textgreater \  \ a^c=b,    where a∈(0;1)∪(1;+oo) and b>0.
2. The variable is only in b, using item 1. it is possible to write: x+3>0. 
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4 years ago
Hilda adds 5 to a number, then multiplies the sum by negative 2. The result is 6. Write and solve an equation to find the number
astraxan [27]

Answer:

I think answer is 3.

Step-by-step explanation:

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5 0
3 years ago
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If a polygon has a vertex at (161, -329) and it is translated 168 units to the right, what are the coordinates of that vertex's
bearhunter [10]
Vertex of the polygon is (161, -329)

The new vertex is shifted 168 units to the right. A horizontal shift can be achieved be adding or subtracting the number from the x-coordinate. A change in the y coordinate brings the vertical shift. So in this case the x-component will change only and y component will be the same.

A shift towards right means, the value of x component is increase as x gets larger as we move towards right on the graph. So moving 168 units to the right, we will get the following vertex (329 , -329)

Thus, the new vertex of the polygon will be at the point (329, -329)
5 0
3 years ago
Pls help I don't get how the school system expects us to know this stuff
Dvinal [7]

Answer:

i've got no idea y they do us dirty like dis

Step-by-step explanation:

1234

8 0
3 years ago
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Write the word sentence as an inequality.<br> One plus a number y is no more than -13.
kolbaska11 [484]

Answer:

1+y \leq -13

Step-by-step explanation:

The problem states that one plus y is No greater than -13.

This means that is less than or equal to -13.

It also gives you one plus y, or 1+y

Put everything together to get 1+y \leq -13

7 0
3 years ago
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