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madam [21]
3 years ago
12

Simplify: (Algebra)

Mathematics
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

2j-3o-5e+l-j+4o+6e= e+j+l+o

-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v

4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r

r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d

t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n

-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a

-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l

-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz

16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in

-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3

-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4

-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is

-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3

r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m

-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4

13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5

-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4

Step-by-step explanation:

a.\ 2j-3o-5e+l-j+4o+6e

Collect Like Terms

-5e+6e+2j-j+l+4o-3o

e+j+l+o

Hence:

2j-3o-5e+l-j+4o+6e= e+j+l+o

b.\ -7d+a+2v-i+8d-v+2i+d^2

Collect Like Terms

d^2+a+8d-7d-i+2i+2v-v

d^2+a+d+i+v

Hence:

-7d+a+2v-i+8d-v+2i+d^2 = d^2+a+d+i+v

c.\ 4a+12r-i+a^2-11r-3a+n+a^3

Collect Like Terms

a^3+a^2+4a-3a-i+n+12r-11r

a^3+a^2+a-i+n+r

Hence:

4a+12r-i+a^2-11r-3a+n+a^3 = a^3+a^2+a-i+n+r

d.\ r^3-11a+12a-sh+2sh+i+d

Evaluate like terms

r^3+a+sh+i+d

Hence:

r^3-11a+12a-sh+2sh+i+d= r^3+a+sh+i+d

e.\ t^5+a-2a+2r-r+l-2l+a^4+3n-2n

Evaluate like terms

t^5-a+r-l+a^4+n

Hence:

t^5+a-2a+2r-r+l-2l+a^4+3n-2n = t^5-a+r-l+a^4+n

f.\ -11i^2-r+2r+a^3-4d+3d-a

Evaluate Like Terms

-11i^2+r+a^3-d-a

Hence:

-11i^2-r+2r+a^3-4d+3d-a = -11i^2+r+a^3-d-a

g.\ -9r+10r+a-s^3-2a+2s^3+u-l

Collect Like Terms

-9r+10r+a-2a+2s^3-s^3+u-l

r-a+s^3+u-l

Hence:

-9r+10r+a-s^3-2a+2s^3+u-l = r-a+s^3+u-l

h.\ -4d+2a^3-a^3+5n+iz-4n

Collect Like Terms

-4d+2a^3-a^3+5n-4n+iz

-4d+a^3+n+iz

Hence:

-4d+2a^3-a^3+5n+iz-4n = -4d+a^3+n+iz

i.\ 16a^5-2(l-y+y3)-a+d^2-d^3+in

Open bracket

16a^5-2l-2y+2y3-a+d^2-d^3+in

Hence:

16a^5-2(l-y+y3)-a+d^2-d^3+in = 16a^5-2l-2y+2y3-a+d^2-d^3+in

j.\ -5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3

Evaluate like terms

-5z+e-y^5+n-a^5-l+l^3-i^3

Hence:

-5z-e+2e-y^5-n+2n-a^5-l+l^3-i^3 = -5z+e-y^5+n-a^5-l+l^3-i^3

k.\ m-3m-a+2a-m^3-2m^5-a^3-d+l+i^4

Evaluate like terms

-2m+a-m^3-2m^5-a^3-d+l+i^4

Hence:

-2m+a-m^3-2m^5-a^3-d+l+i^4= -2m+a-m^3-2m^5-a^3-d+l+i^4

l.\ -4t^3+5t^3+3o-2o+2m-m-r^3-is+2is

Evaluate like terms

t^3+o+m-r^3+is

Hence

-4t^3+5t^3+3o-2o+2m-m-r^3-is+2is = t^3+o+m-r^3+is

m.\ -5j+h-2h+4j-3a+6a-d^3

Evaluate like terms

-5j-h+4j+3a-d^3

Hence:

-5j+h-2h+4j-3a+6a-d^3 = -5j-h+4j+3a-d^3

n.\ r^3-3u+2u-st+a^3-2a^3-5m+4m

Evaluate like terms

r^3-u-st-a^3-m

Hence:

r^3-3u+2u-st+a^3-2a^3-5m+4m = r^3-u-st-a^3-m

o.\ -6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4

Collect Like Terms

-6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4

-6b^5+2a+h+18a^2-d^4-i^2-4r^4

Hence:

-6b^5-a+4h-3h+18a^2+3a-d^4+i^2-2i^2-4r^4= -6b^5+3a-a+4h-3h+18a^2-d^4+i^2-2i^2-4r^4

p.\ 13s^5-2o+5n^3-12s^5-6n^3+3o+a^5

Collect Like Terms

13s^5-12s^5-2o+3o+5n^3-6n^3+a^5

s^5+o-n^3+a^5

Hence:

13s^5-2o+5n^3-12s^5-6n^3+3o+a^5=s^5+o-n^3+a^5

q.\ -17m+16m-3u+r^3+2u-2r^3+a^4+d^4

Collect Like Terms

-17m+16m+2u-3u+r^3-2r^3+a^4+d^4

-m+-u-r^3+a^4+d^4

Hence:

-17m+16m-3u+r^3+2u-2r^3+a^4+d^4= -1m+-u-r^3+a^4+d^4

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Measure of arc = 176°

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To find:

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Solution:

We know that the measure of central angle is equal to measure corresponding intercepted arc and the measure of central angle is twice of the measure of subtended angle on that arc.

So, the measure of arc is twice of measure of subtended angle on that arc.

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