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lys-0071 [83]
2 years ago
13

Sammy starts with $50 in her saving account and adds $50 each week. Write an equation that Sammy can use to show how much money

she has after a certain number of weeks
Mathematics
1 answer:
victus00 [196]2 years ago
7 0

Known facts:

  • 50 dollars is the initial amount in the saving account
  • 50 dollars is added every week into the savings account.

Variables:

  • x: # of weeks
  • y: total amount of money in savings

Set equation based on known facts and variables:

  y = 50x + 50, 50x is the rate at which it grows depending on

   the week and 50 is the initial amount there

Hope that helps!

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7 7/8

Step-by-step explanation:

-3/2 * -5 1/4

= 7 7/8

(Decimal: 7.875)

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Bas_tet [7]

Answer:

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Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?

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2 years ago
Read 2 more answers
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
3 years ago
Abebe is 12 years old and his sister Aster is 2 years old. In how many
Nonamiya [84]

Answer:

Abebe will be exact twice as old as Aster in 8 years.

Step-by-step explanation:

Since Abebe is 12 years old, and his sister Aster is 2 years old, there is a difference of 10 years between them (12 - 2). Therefore, the difference between the two implies that Abebe is exactly twice as old as her sister when she is 10 years old, and she is 20 years old (10 x 2 = 20).

Therefore, since 20-12 equals 8, Abebe will be twice as old as her sister Aster hers in 8 years.

6 0
3 years ago
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