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kupik [55]
3 years ago
6

The heights of women in the united states are normally distributed with a mean of 64 inches and a standard deviation of 2.75 inc

hes. the percent of women whose heights are between 64 and 69.5 inches, to the nearest whole percent, is
a. 6
b. 48
c. 68
d. 95

Mathematics
1 answer:
9966 [12]3 years ago
7 0
According to the normal distribution curve:

<span>"the percent of women whose heights are between 64 and 69.5 inches"</span> represents the values within 2 standard deviation ,,,

And that value is 95% of the whole data



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When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
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and solve for x'.

Hope that helps!
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F(x) is a function.<br> 3<br> 5<br> 2<br> 10<br> 15<br> 0<br> f(x)<br> O A. True<br> O B. False
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Answer:

False

Step-by-step explanation:

X = 5 goes to two different values of y so it is not a one to one correspondence.  This is a relation not a function.

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3 years ago
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3418.05

Step-by-step explanation:

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3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

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  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

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Morgarella [4.7K]

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¾

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