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Scilla [17]
3 years ago
15

“Half of a number (n) is at least 22." translate and solve

Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:

n >_44

Step-by-step explanation:

1/2n>_22

(times 2 on both sides)

n >_44

*** >_ is greater than or equal to sign

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2 years ago
Read 2 more answers
Can someone please explain how to do these?
Pani-rosa [81]

Answer:

<u>First question answer:</u> The limit is 69

<u>Second question answer:</u> The limit is 5


Step-by-step explanation:

For the first limit, plug in x=8 in the expression (9x-3), that's the answer for linear equations and limits.

So we have:

9x-3\\9(8)-3\\72-3\\69

The answer is 69


For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value x=1 into the simplified expression to get the correct answer. Shown below:

\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}

<em>Now putting 1 in x gives us the limit:</em>

\frac{x+9}{x+1}\\\frac{1+9}{1+1}=\frac{10}{2}=5

So the answer is 5

3 0
3 years ago
3 times a number is 54 less than the square of that number. Find the negative solution.
Pavel [41]

Answer:

x=-6

Step-by-step explanation:

Let x be the number

3x = x^2 -54

Subtract 3x

3x-3x = x^2 -3x-54

0 = x^2 -3x-54

Factor

What 2 numbers multiply to -54 and add to -3

-9*6 = -54

-9+6 = -3

0=(x-9) (x+6)

Using the zero product property

x-9=0    x+6=0

x=9  x=-6

The questions asks for the negative solution

x=-6

3 0
3 years ago
Solve for the roots in simplest form using the quadratic formula:<br> 4x2 + 4x = -5
weqwewe [10]

Answer:

Step-by-step explanation:

Move all terms to one side

4x^2 + 4x + 5 = 0

Plug into quadratic formula

x = (-4 <u>+</u> \sqrt{16 - 4(4)(5)}) / 2(4)

  = (-4 <u>+</u> \sqrt{-64})/8

At this point, there are no real answers. The roots to this equation are complex.

x = (-4 <u>+</u> 8i)/8

  = (-1 <u>+</u> 2i)/2

6 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). Round to the nearest tenth if necessa
satela [25.4K]

The standard form for the equation of a circle is :

<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.

 So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :

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 So the point (−9,3) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(−10−(−9))^2+(1−3)^2=1+4=5

 ⇒r=√5

 Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :

 (x+9)^2+(y−3)^2=5

7 0
3 years ago
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