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3 years ago

Can someone pleaseeee help if you’re correct I’ll give u brainlist

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

Step-by-step explanation:

since it is a line segment it is only that portion of a line, so its s, t and all in between

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Help!! 20points! thank you need by tomorrow.

Yakvenalex [24]

Answer:

1. f(x,y) = (x, -y) 2. f(x,y) = (-x,y).

Step-by-step explanation:

I hope that helps

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3 years ago

A box contains 84 chocolates, of which 63 are dark chocolates. The rest are milk chocolates. What is the ratio of milk chocolate

loris [4]

Answer: 21:84

Explanation:

84-63=21, and then just do 21:84 lol

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2 years ago

Help with Algebra 2 thx

Damm [24]

The answer is x=7 hope this helps:)

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2 years ago

Rectangle ABCD is translated (x + 2 y - 3) and then rotated 180° about the origin. Complete the table to show the locations of A

katen-ka-za [31]

Answer:

Step-by-step explanation:

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3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

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3 years ago