Answer:
![v\sqrt[28]{v^{13}}](https://tex.z-dn.net/?f=v%5Csqrt%5B28%5D%7Bv%5E%7B13%7D%7D)
Step-by-step explanation:
The exponent rules that apply are ...
![(a^b)(a^c)=a^{b+c}\\\\a^{\frac{b}{c}}=\sqrt[c]{a^b}](https://tex.z-dn.net/?f=%28a%5Eb%29%28a%5Ec%29%3Da%5E%7Bb%2Bc%7D%5C%5C%5C%5Ca%5E%7B%5Cfrac%7Bb%7D%7Bc%7D%7D%3D%5Csqrt%5Bc%5D%7Ba%5Eb%7D)
Using these rules for your product, we have ...
![v^{\frac{3}{4}}\times v^{\frac{5}{7}}=v^{\frac{3}{4}+\frac{5}{7}}\\\\=v^{\frac{41}{28}}=v\cdot v^{\frac{13}{28}}=v\sqrt[28]{v^{13}}](https://tex.z-dn.net/?f=v%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%5Ctimes%20v%5E%7B%5Cfrac%7B5%7D%7B7%7D%7D%3Dv%5E%7B%5Cfrac%7B3%7D%7B4%7D%2B%5Cfrac%7B5%7D%7B7%7D%7D%5C%5C%5C%5C%3Dv%5E%7B%5Cfrac%7B41%7D%7B28%7D%7D%3Dv%5Ccdot%20v%5E%7B%5Cfrac%7B13%7D%7B28%7D%7D%3Dv%5Csqrt%5B28%5D%7Bv%5E%7B13%7D%7D)
Solution:
we are given that ΔABC and ΔXYZ are similar triangles.
As we know , when two triangles are similar then the ratios of their corrsponding sides are equal.
Here we have
BA = x + 9, AC = x + 7, YX = x + 5, and XZ = x + 4
So we can write
Hence then value of x=-1.
A system of equations may have a single unknown to varying multiples of unknowns , as much the number of unknowns increases , that much system of equations are also built up , else , it can't be resolved
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)
2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)
3. Point (-4, 3) lies in Quadrant II
4. Point (6, 0) lies on the x-axis
5. Any line with no slope is parallel to the y-axis
7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1
8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)
9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6
10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True
Answer:
Reflect the parent function over the x-axis, and translate it 8 units to the left.
Step-by-step explanation:
The given function is
The parent function is
Since there is a negative multiply the transformed function, there is a reflection in the x-axis.
Since 8 is adding, within the square root, there is a horizontal translation of 8 units to the left.
Therefore to graph the given function, reflect the parent function over the x-axis, and translate it 8 units to the left.
