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BabaBlast [244]
4 years ago
7

ΔABC and ΔXYZ are similar triangles. If BA = x + 9, AC = x + 7, YX = x + 5, and XZ = x + 4, find the value of x.

Mathematics
2 answers:
astra-53 [7]4 years ago
7 0

Answer:

-1

Step-by-step explanation:


Nat2105 [25]4 years ago
3 0

Solution:

we are given that ΔABC and ΔXYZ are similar triangles.

As we know , when two triangles are similar then the ratios of their corrsponding sides are equal.

Here we have

BA = x + 9, AC = x + 7, YX = x + 5, and XZ = x + 4

So we can write

\frac{x+9}{x+5}= \frac{x+7}{x+4}\\
\\
(x+9)(x+4)=(x+7)(x+5)\\
\\
x^2+13x+36=x^2+12x+35\\
\\
13x-12x=35-36\\
\\
x=-1\\
\\

Hence then value of x=-1.

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