Answer:
A. ⇒ The expression is b + 3
B. ⇒ The expression is 2b - 4
C. ⇒ The Dr's office is closer by 4 miles
Step-by-step explanation:
A.
∵ The distance between Daniel's house and his school is b miles
∵ The swimming pool is 3 miles farther from his school
∴ The distance between Daniel's house and the swimming pool is b + 3
B.
∵ The distance from Daniel's house to his Dr's office is 4 less than twice the distance from home to Daniel's school
∵ The distance between Daniel's house and his school is b
∴ The expression of distance from Daniel's house to his Dr's office is
2b - 4
C.
∵ b = 3
∴ The distance between his house and swimming pool is:
3 + 3 = 6 miles
∴ The distance between his house and Dr's office is:
2(3) - 4 = 2 miles
∴ The Dr's office is closer to Daniel's house than the swimming pool by:
6 - 2 = 4 miles
Answer:
-6.3
Step-by-step explanation:
2.6 * 10 (10 hours and 2.6 degrees) = 26
19.7 - 26 = -6.3
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Firstly 31*4=124
1*3=3
124-3=121
121/12
Answer:
A
Step-by-step explanation:
small dog eats 3/4 cup each day
large dog eats 1 cup each day
~after 1 week (x7)~
small dog = 5.25 cups
large dog = 7 cups
(7-5.25=1.75)
= therefore 1 and 3/4 cups
