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3 years ago

6

Rewrite the expression in standard form ( use the fewest number of symbols and characters possiable). a. 5g•7h b.3•4•5•m•n

1 answer:

CaHeK987 [17]3 years ago

6 0

Answer:

a. 35 *gh or 35 gh

b. 60 *mn or 60 mn

Step-by-step explanation:

The fewest number of symbols and characters can be obtained by multiplying the constant numbers with the constant numbers and variables with the variables.

a. The co efficients 5 and 7 are multiplied to get 35 and g is multiplied with h to get gh. So the answer is 35*gh. It can be further simpliefied into 35 gh

b. The co efficients 3,4 and 5 are multiplied to get 60 and m is multiplied with n to get mn. The answer is 60* mn. On further simplificaation we get 60 mn.

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The answer is 12 percent change

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In 2007, there were more than 8.14 million cars for sale. Over the next 3 years, the number of cars decreased by 23%. Write an e

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Answer:

c = 8.14 million×(0.9166)^t

4.83 million

Step-by-step explanation:

Data:

t = y - 2007

c₀ = 8.14 million

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Part 1. Calculate c₃

c₃ = c₀(1 - 0.23) = 0.77c₀

Part 2. Calculate r

c₃ = c₀r^t

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The explicit decay model is c = 8.14 million×(0.9166)^t

Part 3. Prediction

t = 2013 - 2007 = 6

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3 years ago

Select the correct answer.

sladkih [1.3K]

Answer:

A

Step-by-step explanation:

Because this ia so simple I don't even need to explain to waste my last few brain cells.

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3 years ago

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Verify: sec^2x+tan^2x=2sec^2x-1

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Answer:

see explanation

Step-by-step explanation:

Using the identity

tan²x = sec²x - 1

Consider left side

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3 years ago

The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How lo

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Answer:

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Step-by-step explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula

$A=P(2)^\frac{t}{24}$

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P is the initial amount that is 500

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On substituting the values in the formula we get

$800=500(2)^\frac{t}{24}$

On simplification we get

$\Rightarrow\frac{8}{5}=(2)^\frac{t}{24}$

Taking log on both sides we get

$\Rightarrow\log\frac{8}{5}=\log(2)^\frac{t}{24}$

using $\log\frac{m}{n}=\log m-\log n$

And $\log a^m=m\log a$

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$\Rightarrow 0.903-0.698=\frac{t}{24}0.301$

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$\Rightarrow t=16.34$

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3 years ago

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