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djyliett [7]
3 years ago
6

Rewrite the expression in standard form ( use the fewest number of symbols and characters possiable). a. 5g•7h b.3•4•5•m•n

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

Answer:

a. 35 *gh or 35 gh

b. 60 *mn or 60 mn

Step-by-step explanation:

The fewest number of symbols and characters can be obtained by multiplying the constant numbers with the constant numbers and variables with the variables.

a. The co efficients 5 and 7 are multiplied to get 35 and g is multiplied with h to get gh. So the answer is 35*gh. It can be further simpliefied into 35 gh

b. The co efficients 3,4 and 5 are multiplied to get 60 and m is multiplied with n to get mn. The answer is 60* mn. On further simplificaation we get 60 mn.

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Answer:

21.8

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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EleoNora [17]

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c is the answer for number 6 and

Step-by-step explanation:

and b is the answer for number 7

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IrinaVladis [17]

Answer:

Part A: a histogram

Step-by-step explanation:

Part A:

A histogram would be the best to use since they gave values that are x - y, or a ranged amount for the score.

Part B:

You would set up each value for the scores on the bottom. You would make the number of students on the left in increments of 1 (1,2,3,4,5 etc. )

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8 0
3 years ago
A fence is to be built to enclose a rectangular area of 1800 square feet. The fence along three sides is to be made of material
drek231 [11]

Answer:

length = 60 foot, width = 30 foot

Step-by-step explanation:

Area of rectangular part, A = 1800 ft²

Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.

Let the length of the rectangle is l and the width of the rectangle is W.

Area = Length x width

A = L x W

1800 = L x W ...... (1)

Total cost of fencing, C = 6 x ( L + W + L) + 18 x W

C = 6 (2L + W) + 18 W

C = 12 L + 24 W

Substitute the value of W from equation (1), W=\frac{1800}{L} in equation (2)

C=12L+24\times \frac{1800}{L}

C=12L+\frac{43200}{L}

Differentiate both sides with respect to L:

\frac{dC}{dL}=12-\frac{43200}{L^{2}}

Put it equal to zero for maxima and minima

12-\frac{43200}{L^{2}}=0

L = 60 foot

and W = 30 foot

So, the costing is minimum for length = 60 foot and the width = 30 foot.

4 0
3 years ago
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