The fewest number of symbols and characters can be obtained by multiplying the constant numbers with the constant numbers and variables with the variables.
a. The co efficients 5 and 7 are multiplied to get 35 and g is multiplied with h to get gh. So the answer is 35*gh. It can be further simpliefied into 35 gh
b. The co efficients 3,4 and 5 are multiplied to get 60 and m is multiplied with n to get mn. The answer is 60* mn. On further simplificaation we get 60 mn.
