Answer:
I do not know, if you ca rewrite that would be helpful
Step-by-step explanation:
Answer:
the daily fee =33 dollars
and the mileage charge.=0.35
Step-by-step explanation:
let d: be daily fee and m for mileage
cost of rental =(d*number of days)+ (m*number of mileage)
her first trip: 4d+440m=286
her second trip: 3d+190m=165.5
solve by addition and elimination
4d+440m=286 ⇒ multiply by 3 ⇒12d +1320m=(3)286
3d+190m=165.5⇒ multiply by 4⇒12d+190(4)m=4(165.5)
12d+1320m=858
12d+760m=662
subtract two equation to eliminate d
12d+1320m-12d-760m=858-662
560m=196
m=7/20=0.35 for on mileage
d: 4d+440m=286
4d=286-440(0.35)
d=(286-154)/4 33 dollars
The answer is 96.
The 3,a,b,& c cancel out because they equal 1.
Then your left with 48*2 which is 96.
48 * a * 3 * b * c * 2--------------------------3 * a * b * c
3/3 = 1 B/b = 1 C/c = 1
1 * 1 * 1 * 48 * 2 = 96
Addition subtraction multiplication or division
