3 years ago

Write the canonical equation of the straight line 2x+3y-2z+6=0, x-3y+z+3=0

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

6 0

i hope this helps

let me know if im wrong

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45÷___=-5 what is the answer?

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Lubov Fominskaja [6]

Answer:

The answer is " $\sqrt[8]{2^5}$ ".

Step-by-step explanation:

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$\to \frac{2 \frac{7}{8}}{2 \frac{1}{4}}$

They understand that, by using algebraic expressions laws, they subtract that inverse whenever we subtract powers with the same base. Every exponent's core is 2, therefore we subtract:

$\to \frac{7}{8} - \frac{1}{4}$

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among 8 or 2 is 8:

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This gives us:

$\to 2 \frac{5}{8}$

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Which means 8 is the root and 5 the force that gives us:

$\sqrt[8]{2^5}$

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