-(4/5)*(3/7)*(15/16)*(-14/9) [two negatives make one positive]
=(4*3*15*14)/(5*7*16*9) [simplify 4/16]
=(3*15*14)/(5*7*4*9)
=(3*3*14)/(7*4*9)
=(14)/(7*4)
=(2)/(4)
=1/2
Answer:

Step-by-step explanation:
Given

Required
Determine the area with coordinates 
The area is represented as:

Where

and

Substitute values for r, a and b in


Expand


By integratin the above, we get:
![Area = \frac{1}{2}*\frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{2}[0,2]](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B%28cos%28%5Ctheta%29%20%2B%204%29sin%28%5Ctheta%29%20%2B%203%5Ctheta%7D%7B2%7D%5B0%2C2%5D)
![Area = \frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{4}[0,2]](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B%28cos%28%5Ctheta%29%20%2B%204%29sin%28%5Ctheta%29%20%2B%203%5Ctheta%7D%7B4%7D%5B0%2C2%5D)
Substitute 0 and 2 for
one after the other





Get sin(2) and cos(2) in radians


