Given a right triangle with an acute angle Θ , if sin Θ = cos Θ , describe what this triangle would look like.
1 answer:
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Image is missing, so i have attached it.
Answer:
AC = 10sin 40°
Step-by-step explanation:
From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.
Thus, since we want to find AC;
We know that in trigonometric ratios; opposite/hypotenuse = sin θ
In the diagram, θ = 40° and AB = 10
Thus,
AC/10 = sin 40°
Multiply both sides by 10 to get;
AC = 10sin 40°
