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3 years ago

Solve the inequality please .. if you can show your work i dont understand it

Mathematics

1 answer:

Sauron [17]3 years ago

4 0

Answer:

X ≥ 3

Step-by-step explanation:

First you simplify, as if the ≤ is an = (just don't multiply with a negative number)

27 = 7X + 6

27 - 6 = 7X

21 = 7X

3 = X

Then you put the ≤ back in

3 ≤ X

and put the X up front. The ≤ then swaps into a ≥

Finally, you can do a test with X = 2 (should be false) and X=4 (should be true), to check wether you made any mistakes.

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What is the value of the expression?

Lady bird [3.3K]

Answer:

690

Step-by-step explanation:

(323+1715)-(1135+213)

(2038)-(1348)

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3 years ago

Taylor can clean pools at a constant rate of 2/5 pools per hour. What is the ratio of pools to hours? HELPP PLEASE

Hatshy [7]

Hi! I'm happy to help!

To solve for this, we need to understand what a ratio is. A ratio is a comparison between two things. (in numbers) In this case, between pools and hours:

pools:hours

A fraction is also a ratio, in this case we have 2/5, which also compares pools to hours, so we can turn this into a more proper ratio form:

2 pools: 5 hours

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So, our ratio of pools to hours is 2:5.

I hope this was helpful, keep learning! :D

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Julio bought 12 bulbs of jumbo garlic for $11.88. How many bulbs of jumbo garlic can Anjali buy if she has $3.96?

Molodets [167]

Answer:

Anjali can buy 4 bulbs of jumbo garlic if she has $3.96.

Step-by-step explanation:

To calculate how many bulbs of jumbo garlic Anjali can buy with $3.96, we must first calculate the unit rate of the jumbo garlic. Julio buying 12 bulbs of jumbo garlic for $11.88 can be represented as:

$\frac{11.88}{12}$

Divide the fraction by $\frac{12}{12}$ to calculate the unit rate:

$\frac{.99cents}{1bulb}$

So if each bulb of garlic costs $0.99, which we can think of as being $1.00 at the moment, we could figure that Anjali's $3.96 would be closer to $4 than it is to $3, so let's multiply the unit rate by $\frac{4}{4}$ :