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3 years ago

Heeeeeeeeeelpppppppp meeeeeeee

Mathematics

1 answer:

Step2247 [10]3 years ago

6 0

Answer: The answer is 10.5

Step-by-step explanation: for subtracting the answer is 1.5 and for multplying its 39.375 and last for division its 0.51428571428 *lol*

Have a wonderful day! ^-^

You might be interested in

10 yards 1 foot 9 inches divided by 3

AysviL [449]

Answer:

127 inches

Step-by-step explanation:

A single yard is equal to 3 feet. So one yard 1 foot and 9 inches is:

$3(10)+1$ and 9 inches.

each feet has 12 inches, so it goes something like this:

$12(31)+9$ inches

multiply it out:

$372+9\\381$

Thats the total number of inches, now we divide by 3 (use long division:

$\frac{381}{3}=127$

Hope this helps!

6 0

3 years ago

PLS HELP ILL GIVE BRAINLIST!

lyudmila [28]

Answer:

Step-by-step explanation:

A2+B2=C2

A2+15squared=17squared

A2+225=289

289-225=64

A2=64

64 squared is 8

7 0

3 years ago

Jim earns $1,600 per month after taxes. He is working on his budget and has the first three categories finished.

ivann1987 [24]

He is budgeting too much for transportation. He has used the highest recommended percentages to calculate the amounts for the three categories. He is budgeting too much for housing. He has used the lowest recommended percentages to calculate the amounts for the three categories. hope this helps :)

6 0

3 years ago

Read 2 more answers

Can you explain plz help

melomori [17]

Answer

0.7625

Explaination

Divide the numbers

6.1/8 = 0.7625

8 0

3 years ago

21. In 4 + In(4x - 15) = In(5x + 19)

Alexxx [7]

Answer:

$x=-30;\quad \:I\ne \:0$

Step-by-step explanation:

$In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)$

$\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\$

$\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\$

$\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:$

$\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0$

3 0

3 years ago