Use the distributive property to expand the following expression (9m-6)7
1 answer:
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- The Midpoint of AB is (1,0).
Given that:
- In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).
To find:
- The Midpoint of line AB.
So, according the question
We know that,
The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M ( ).
Now from question,
We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.
So, we can say that
A is (3,1) or x₁ = 3 and y₁ = 1.
B (-1,-1) or x₂ = -1 and y₂ = -1.
∵ The coordinates of midpoint M (X,Y)
X =
=
= 2/2
X = 1.
And
Y =
=
= 0/2
Y = 0.
So, the midpoint of line AB is M (1,0)
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f-¹(x)=
Answer:
Solution given:
f(x)=
Let f(x)=y
y=
Interchanging role of x and y
x=
doing crisscrossed multiplication
x(y+7)=-2y+2
now solve it:
xy+7x=-2y+2
keep like terms in one side
xy+2y=2-7x
take common
y(x+2)=2-7x
make a value of y
y=
So,
f-¹(x)=