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kow [346]
3 years ago
13

Find an angle at home. Measure the angle. Record the measure. Classify the angle.

Mathematics
1 answer:
Svetllana [295]3 years ago
7 0
A table leg. It is 90 degrees from the floor. It is a right angle
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During a cold winter, the temperature stayed below zero for 10 days (ranging from −20 to −5). The variance of the temperatures o
Serjik [45]

Answer:

The variance of the temperatures of the 10 day period must be at least zero.

Step-by-step explanation:

The variance is the expectation of the squared deviation of a random variable from its mean. It measures how far a set of numbers are spread out from their average value.

Its unit of measure corresponding to the square of the unit of measure of the variable. In this case, the variance of the temperatures is expressed in (°C)². The variance has a minimum value of 0.

Since the variance is squared, it will always have values greater than zero.

5 0
3 years ago
If x and y vary inversely and x = 5 when y = -3.5, what is the value of x when y = 10?
Solnce55 [7]

Answer:

Step-by-step explanation:

k = xy

Putting values of x and y in the equation

k = (5)(-3.5)

= - 17.5

Finding value of x when y = 10

k = xy

- 17.5 = x10

Bringing like terms on one side

- 17.5 - 10 = x

-27.5 = x

5 0
3 years ago
Which statement best describes the area of Triangle ABC shown below?
sergij07 [2.7K]
The answer is b ...........................................................b............b..............

8 0
3 years ago
Read 2 more answers
theresa went bowling on tuesday night. she bowled scores of 150, 165, and 165. what was her mean average score?
aleksley [76]
So, to do this, all you need to do is add up all the values, and then, with that number, divide by how many values are given.

150+165+165= 480
480/3= 160

7 0
3 years ago
Read 2 more answers
An object is acted upon by the forces F1=<10​,6​,4> and F2=<0​,3​,9>. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
2 years ago
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