I really need the help please and thank you

Rebecca measured herself and she was 52 in tall how many feet tall was she

Drupady [299]

Hi there!☺

52 inches in feet would be about 4.3 feet.

~Elisabeth

8 0

3 years ago

A researcher expects a treatment to produce an increase in the population mean. The treatment is evaluated using a one tailed hy

Shkiper50 [21]

Answer:

A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.

Step-by-step explanation:

State the null and alternative hypotheses to be tested

On this case we can assume that the researcher conduct a one right tailed test hypothesis like on this way:

Null hypothesis: $\mu \leq \mu_o$

Alternative hypothesis: $\mu > \mu_o$

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

On this case we have the value for z score given z =+1.85

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05,0.01$ . The next step would be calculate the p value for this test.

Since is a one right tail test the p value would be:

$p_v =P(z>1.85)=1-P(Z$

If we compare the p value obtained and the significance level given $\alpha=0.05,0.01$ we can take a decision:

A) The researcher should reject the null hypothesis with a = .05 but not with a = .01.

YES, since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level. And for the significance level 0.05 we have that $p_v$ and we can reject the null hypothesis.

B) The researcher should reject the null hypothesis with either a = .05 or a = .01.

No since the p value it's higher than the significance level of 0.01 so we FAIL to reject the null hypothesis at this significance level

C) The researcher should fail to reject H0 with either a = .05 or a = .01.

No, for the significance level of 0.05 we reject the null hypothesis since $p_v$

D) This cannot be answered without additional information.

No, we have enough info to answer the question

4 0

4 years ago

CHECK Mynicknameisnickname THEY HAVE THIS QUESTION FOR 100 POINTS FOR THE FIRST CORRECT PERSON HURRY!!

mars1129 [50]

Let "c" and "q" represent the numbers of bottles of Classic and Quantum that should be produced each day to maximize profit. The problem conditions give rise to 3 inequalities:
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.

Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.

To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.

Profit will be 6899p per day.

_____
The problem statement gives no clue as to the currency equivalent of 100p.