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lakkis [162]
3 years ago
10

I really need the help please and thank you

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Asnwer: C

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I NEED HELP REALLY FAST!!!
nadya68 [22]
Explain the question?
3 0
3 years ago
System OT<br> W + b =13<br> 6.5w + 2b = 57.5
mixer [17]

Answer:   w = 7,  x = 6

Step-by-step explanation:  Solve by substitution

W + b = 13

rewrite as   b = 13 - w  and substitute that value for b in the second equation

6.5w + 2b = 57.5  Then solve for w

6.5w + 2(13-w) = 57.5 . Distribute

6.5w + 26 - 2w = 57.5 .  Subtract 26 from both sides. Combine like terms and simplify

6.5w - 2w = 57.5 - 26

4.5w = 31.5  Divide both sides by 4.65

w = 7 . Substitute 7 for w in the first equation and solve for b

7 + b = 13 . Subtract 7 from both sides

b = 6

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3 years ago
How many servings can you provide if you cut the recipe in half
Ilia_Sergeevich [38]

Answer:

Half of the original amount of servings.

7 0
3 years ago
En la final de un concurso escolar de
Sati [7]

Usando la distribución hipergeométrica,  la probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es: 0.2 = 20%.

<h3>¿Qué es la fórmula de distribución hipergeométrica?</h3>

La fórmula es:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • x es el número de éxitos.
  • N es el tamaño de la población.
  • n es el tamaño de la muestra.
  • k es el número total de resultados deseados.

Los valores de los parámetros son:

N = 6, k = 3, n = 2.

La probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es P(X = 2), por eso:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,3) = \frac{C_{3,2}C_{3,0}}{C_{6,2}} = 0.2

Puede-se aprender más a cerca de la distribución hipergeométrica en brainly.com/question/24826394

#SPJ1

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Increase £19028.42 by 9.5%<br> Give your answer rounded to 2 DP.
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