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Dmitry [639]
3 years ago
14

Help me plz!!!!!!!!!!!!!!!

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

what is your queitiion

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The product is -12 for this problem
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HELPPPP PLEASE!!!!!!
worty [1.4K]

Answer:

<h3>y = 20</h3><h3 />

Step-by-step explanation:

line RPN = 180 = 4y - 10 + 90 + y

180 - 90 + 10= 5y

100 = 5y

y = 100/5

y = 20

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3 years ago
1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit
Stels [109]
\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})

"Chocolate" has the marginal distribution given by the second column, with a total probability of P(\text{chocolate})=0.35. Similarly, "Adults" has the marginal distribution described by the third row, so that P(\text{adults})=0.60. Then

P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with P(\text{chocolate}\cap\text{adults})=0.21.

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;


P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14
P(\text{children}\cap\text{chocolate})=0.14

c. Yes;

P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26
P(\text{vanilla}\cap\text{children})=0.26
5 0
3 years ago
Please help me with this question
melamori03 [73]

Answer:

1.4

Step-by-step explanation:

hope it helped

8 0
3 years ago
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