The coefficient of the squared expression is 1/9
<h3>How to determine the coefficient of the squared expression?</h3>
A parabola is represented as:
y = a(x - h)^2 + k
Where:
Vertex = (h,k)
From the question, we have:
(h,k) = (-2,-3)
(x,y) = (-5,-2)
So, the equation becomes
-2 = a(-5 + 2)^2 - 3
Add 3 to both sides
1 = a(-5 + 2)^2
Evaluate the sum
1 = a(-3)^2
This gives
1 = 9a
Divide both sides by 9
a = 1/9
Hence, the coefficient of the squared expression is 1/9
Read more about parabolas at:
brainly.com/question/4061870
#SPJ1
1) 2
2) 3
3) 4
4) 7
Hope this helps ^-^
Area = side AB * side BC = (5x + 5x + 3)(3x + 92x - 4)
= (10x + 3)(95x - 4) = 950x^2 - 40x + 285x - 12
= 950x^2 + 245x - 12 Answer
This cannot be negative so restriction on x is 950x^2 + 245x > 12
That is x > 0.0421
<h3>
Answer: Choice B</h3>
No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.
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Explanation:
The greek letter mu is the population mean. It has the symbol
which looks like the letter 'u' but with a tail at the front or left side.
The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8
We see that 5 is <u>not</u> in that interval. It's a bit to the left of 5.2
Since mu = 5 is not in the interval, it's not a plausible value for the population mean.
Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.