The expression is: 2c + 5
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Let Q(t) = the mass (mg) remaining after t hours.
We are told that Q diminishes by 3% every hour.
When t = 0, Q = 4 mg
When t = 1, Q = 4*0.97 mg
When t = 2, Q = 4*(0.97)² mg
By induction,

Q'(t) = 0.97Q
Therefore the rate of decrease is 3% per hour.
The person receives an additional dosage when Q falls to 0.50 mg. This happens when

After the second injection, the mass is now 4.5 mg. Therefore

When the mass again reaches 0.50 mg, then

Answers:
(a)

(b) 3% per hour
(c) 68.3 hours
(d) 72.1 hours
Answer:
The chemical element loses 4% of its weight everyday
Step-by-step explanation:
Here, we are interested in knowing the percentage weight loss of the chemical each day.
The key to answering this is looking at the expression inside the bracket.
We can express M(t) = 169•(0.96)^t as
M(t) = 169•(1-0.04)^t
So what this means is that we need to find the percentage value corresponding to 0.04 since it is a constant term here
Mathematically, 0.04 is same as 4/100, so we can clearly say that the constant percentage loss is 4%
Answer: - 23/12
decimal -1.916
Step-by-step explanation:
Answer:
d <-15
In interval notation
(-∞,-15)
Step-by-step explanation:
-7d>105
Divide each side by -7. remembering to flip the inequality
-7d/-7 < 105/-7
d <-15