The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)
----------------(from equation 1)
----------------(given p=58 inches)
----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.
as, 
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer: y + 4 = -3(x+1)
Step-by-step explanation:
We need to rewrite in form of y=mx+b.
3x+y=5
y = -3x + 5
The slope is -3.
In addition, the slope of two parallel line would be equal, the slope of the line would be -3.
y- y1 = m(x- x1)
y- (-4) = -3(x - -1)
y + 4 = -3(x+1)
3926/13 =302 but I'm not 100% sure where you went wrong do you have any work?
Answer:
<h2>x = 3 and x = 4 → (3, 0) and (4, 0)</h2>
Step-by-step explanation:
This might not be correct but....
I’m going to use rounding,
42 x 2 = 84
84 divides by 3 = 28,
Which is near 30......So the number of people in the group is rounding to about 2 people.
