1233mZXOZ
Step-by-step explanation:
C . no solution , that’s what I think :)
It seems that some the work is already here, but I'd be glad to!! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that's as far as you can factor.
For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)
For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)
Hope this helps!
Answer:
<h2>an+1 = 2×7ⁿ</h2>
Step-by-step explanation:
98÷14
=7
686÷98
=7
4 802÷686
=7
33 614÷4 802
=7
Then the common ratio q for this sequence is 7
recursive formula : an+1 = q×an = ?
an= a1 × qⁿ⁻¹
=2×7ⁿ⁻¹
an+1 = q×an
= 7×(2×7ⁿ⁻¹)
= 2×7ⁿ
