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bixtya [17]
3 years ago
15

Nick works part-time at a bookstore. His pay varies directly with the number of hours worked. In one week, he earned $120 for 8

hours of work.
a) Define two variables for this relation.



b) Describe the rate of change in words.


c) Determine an equation to represent the relation:


d) Use the equation to determine how many hours Nick must work to earn $345
Mathematics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer:

23 hoiurs

Step-by-step explanation:

Given data

a. The two variables are

1. Number of hours worked

2. The amount earned

b. The rate is given as

=120/8

=$15 per hour

c. The equation is given as

rate=Amount earned/ number of hours worked

15= 345/hours

make hours subject of the formula we have

hours= 345/15

hours= 23 hours

Hence he must work for 23 hours

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Tema [17]

Answer:

Surface Area = 85.75 ft²

Step-by-step explanation:

Surface area of pyramid = ½(Perimeter of triangular base * slant height of pyramid) + Area of triangular base

Perimeter of triangular base = sum of all sides of the triangular base = 5+5+5 = 15 ft

Slant height of pyramid = 10 ft

Area of triangular base = ½*base of triangle*height of triangle = ½*5*4.3 = 10.75 ft²

Plug in the above values:

Surface Area = ½(15*10) + 10.75

= (15*5) + 10.75

= 75 + 10.75

Surface Area = 85.75 ft²

8 0
4 years ago
Solve −5+1/4x=3x+6 by graphing.
erma4kov [3.2K]

Answer:

hope its right lol

5 0
3 years ago
Solve for g<br>-6g + 3g + 12 &gt; -18<br>A.g&lt;2<br>B.g&gt; 2<br>C.g&lt;10<br>D.g&gt; 10​
Minchanka [31]

Answer:

g < 10

Step-by-step explanation:

-6g + 3g + 12 > -18

Combine like terms

-3g +12 > -18

Subtract 12 from each side

-3g+12-12 > -18-12

-3g > -30

Divide each side by -3, remembering to flip the inequality

-3g/-3 < -30/-3

g < 10

4 0
3 years ago
Which line has a slope of -1/2 A,B,C,D
melamori03 [73]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
Read 2 more answers
(Hypothetical.) Suppose five measurements of the volume of a liquid yield the following data (in milliliters).
Digiron [165]

Answer:

The 95% confidence interval for the measurements is [48.106, 53.494].

Step-by-step explanation:

The average M of this sample is

M=\dfrac{1}{5}\sum_{i=1}^5x_i=\dfrac{1}{5}(52+48+49+52+53)\\\\\\M=\dfrac{254}{5}=50.800

The standard deviation s of this sample is

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^5(x_i-M)^2}

s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}

s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168

The degrees of freedom are

df=n-1=5-1=4

Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.

The margin of error of the CI is:

E=t\cdot s/\sqrt{n}=2.776\cdot 2.17/\sqrt{5}=6.024/2.236=2.694

Then, the lower and upper bounds of the CI are:

LL=50.800-2.694=48.106\\\\UL=50.800+2.694=53.494

The 95% confidence interval for the measurements is [48.106, 53.494].

4 0
4 years ago
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