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3 years ago

9

Math help? 10 points!

1 answer:

Kipish [7]3 years ago

4 0

Perimeter is when you add all the sides together...but oh, no! There are two sides missing! So we have to find it. The horizontal like could be x and the vertical, the y. x would be 3 because one side is 7 and the other side is 4, so if we subtract them, we get 3. Same for the vertical, the y would be 3. (3+3=6)

Now we could add all sides to get the last choice, or 26 cm.

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50 points please help

ioda

4x row 3 box 2 that’s the only one I know

8 0

3 years ago

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Please help I don’t understand

maria [59]

Answer:

f= 11

Explanation:

f= 2t-3 when t= 7 (just plug in 7 for the variable t!)

f= 2(7)-3

f= 14-3

f= 11

3 0

3 years ago

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A cylinder has a height of 8.1 inches and circular base with a diameter of 2.7 inches. The cylinder contains 3 green spheres, ea

klasskru [66]

Answer:

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

Step-by-step explanation:

Let's find volume of the cylinder and volume of the three spheres.

Volume of cylinder = $\pi r^{2} h$

Volume of sphere = $\frac{4}{3} \pi r^{3}$

Now, r =2.7

h=8.1

Find volume of each shape.

Volume of cylinder = $\pi (2.7)^{2} (8.1)$

=59.049 $\pi$

Now, volume of 3 spheres = $3*\frac{4}{3} *\pi *(2.7)^{3}$

=78.732 $\pi$

Now, p(E)= $\frac{Outcomes favorable to event E}{Total number of outcomes}$

So, Probability of point is chosen at random inside the cylinder which belongs outside of the spheres is

$\frac{78.732\pi -59.049\pi }{78.732\pi }$

Let's simplify them

0.25

A point is chosen at random inside the cylinder, then probability the point belongs outside of the spheres is 0.25

6 0

3 years ago

Find the sum using front end estimation.

dlinn [17]

Answer:

1690 (C)

Step-by-step explanation:

Just Add

237

549

904

--------

1690

8 0

4 years ago

Question 19 of 28

Goryan [66]

Answer:

BC^2=10^2+30^2

Step-by-step explanation:

P=10
B=30

Using pythagorean theorem

$\\ \sf\longmapsto BC^2=10^2+30^2$

$\\ \sf\longmapsto BC^2=100+300$

$\\ \sf\longmapsto BC^2=400$

$\\ \sf\longmapsto BC=\sqrt{400}$

$\\ \sf\longmapsto BC=20$

8 0

3 years ago