Answer:
string=""
while string not in {"Quit","quit","q"}:
string=input("Enter line to be reversed") #line of text will be entered
if string!="Quit" and string!="quit" and string!="q": #If quit is not entered
print("Reverse of line is : ")
print(string[::-1])
OUTPUT :
Enter line to be reversedThis code is in python language
Reverse of line is :
egaugnal nohtyp ni si edoc sihT
Enter line to be reversedHello world
Reverse of line is :
dlrow olleH
Enter line to be reversedquit
Explanation:In the above program, First a while loop is executed and checked if line of text is not 'quit', 'Quit' or 'q'. If condition is true, then loop is executed and in python any string or list can be traversed from end if step is given -1. Similarly line of text is accessed from the last element. If quit is entered, then the program will be broken out of the loop.
Answer:
A. Document Properties
B. Permission
C. Document Options
D. File Details
The answer to this question is "File Details
" . This will help Jeffrey works efficiently with a huge database of spreadsheet records each day. He can assign names to these File Details which represents each spreadsheet records. This will help his report more organized and easy to identity.
This would be copy and paste.
When you select a text, you can use your keys CTRL and C to copy that same selected text. After this, you can use the paste feature by selecting CTRL and V. Doing this, your selected text will be copied and pasted to a certain location.
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
The union of two tables is basically the total of the two tables, so "or" questions would be my guess.
