Answer:
Please check the attachment.
for the assembly language program the jump and move keywords have been used to establish the if else ladder.
Also for the best three marks, we need to store the three theory and two practical marks in an array, and then we can sort it to get the best three marks to find the CA. and then from initial array, we can find the last two practical test parks, and find their average.
Rest of the calculation is as being mentioned in the image. Also, in the image we have 2 practicals. We need to count two instead of three there, and rest is as shown.
Explanation:
The answer does not require any further explanation.
Answer:
69.08265412 milliseconds
Explanation:
Lets first convert 7 MiB to bits
bits
Now convert bits to Gbits
Gbits
Queuing Delay = Total size/transmission link rate
Queuing Delay= 
seconds
Delay of packet number 3 = 
seconds
or 
milliseconds
Graphic images can be stored in a variety of formats including JPEG and GIF. Hope this helped!
Answer:
Used the command syntax; awk -F":" '{ print "username: " $<number location> "\t\tuid:" $<number location> }' <target folder>
Explanation:
Linux operating system is a fast open-source computer platform for programmers and network administrators. Its system is arranged in a hierarchical tree structure with the root represented as "/" (for absolute path).
The passwd is a folder in the Linux OS that holds the login details of all users in the system network. The 'awk' is one of the commands used to get information from a file in a folder. It prints out the result by specifying the location of the values (like the username and user id) as a variable (with prefix '$') and then the target folder.
