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ElenaW [278]
3 years ago
13

WIL GIVE BRAINLIEST Focus (- 2, - 3) Directrix x = 6

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

Here's ya answer!

(

y

+

3

)

2

=

−

6

(

x

−

7

2

)

Sorry its upside down, but good luck on that test!

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Which quadratic function is represented by the table ???
Ulleksa [173]

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A.   3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 -  4 - 5

12 - 9

= 3

B.   3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C.   2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D.   2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

8 0
3 years ago
A square has an area of 289 sq cm. what is the length of one side
Elodia [21]
289 square root = 17
17*17=289
Say 17 was length and 17 was width. L*w=289
Also, all sides of the square are the same.
5 0
3 years ago
Geometry Question attached below
Soloha48 [4]

I'm sure there's an easier way to do this, but this method does work:

First, AB = CD = CG + GF + FD, so FG = 2.

By the Pythagorean theorem, in triangle AFD we get

1^2+3^2=A F^2\implies A F=\sqrt{10}

and in triangle BCG,

2^2+3^2=BG^2\implies BG=\sqrt{13}

Angles AFD and EFG form a vertical pair, so they are congruent and have measure

m\angle EFG=\tan^{-1}3

Similarly, angles BGC and FGE are congruent and have measure

m\angle FGE=\tan^{-1}\dfrac32

Then the remaining angle in triangle EFG has measure

m\angle FEG=\pi-\tan^{-1}3-\tan^{-1}\dfrac32

We can solve for the lengths of FE and GE exactly by applying the law of sines:

\dfrac{\sin\left(\pi-\tan^{-1}3-\tan^{-1}\frac 32\right)}2=\dfrac{\sin\left(\tan^{-1}3\right)}{GE}=\dfrac{\sin\left(\tan^{-1}\frac32\right)}{FE}

\implies GE=\dfrac{2\sqrt{13}}3,FE=\dfrac{2\sqrt{10}}3

Let s be the semiperimeter of triangle ABE, so that

s=\dfrac{AB+BE+EA}2

Then according to Heron's formula, the area of triangle ABE is

\sqrt{s(s-AB)(s-BE)(s-EA)}=\dfrac{25}2

5 0
4 years ago
What is the probability a sample of 66 test takers will provide a sample mean test score within 10 points of the population mean
tatyana61 [14]

This question is incomplete, the complete question is;

A certain organization reported the following scores for two parts of the scholastic Aptitude test ( SAT)

Evidence-based Reading and writing  : 533

Mathematics                                           : 527

Assume the population standard deviation for each part is σ = 100.

What is the probability a sample of 66 test takers will provide a sample mean test score within 10 points of the population mean of 533 on the Evidence-based Reading and Writing part of the test?

Answer: the required probability is 0.582

Step-by-step explanation:

Given that;

Population mean = 533

sample size n = 66

population standard deviation σ = 100

σ of x bar = 100/√66 = 12.3091

Normal distribution with mean 533 and SD of 12.3091

P( 523 <x< 543 )

Z = 10 / 12.3091

Z = 0.8124, -0.8124

P( z < 0 0.8124) - P( z < -0.8124)      { from table}

⇒  0.7910 - 0.2090

= 0.582

Therefore, the required probability is 0.582

4 0
3 years ago
Using the following data state errors in the box and whisker plot 33,27,6,34,31,59,26,1,30
ratelena [41]

AnswerStep-by-step explanation:

To find out the errors made in the data plot, let's determine what the five-number summary of the data set that should be displayed by the box plot should be.

First, order the data set given:

1, 6, 26, 27, 30, 31, 33, 34, 59

The five-number summary are:

1. Min value = 1

2. Max value = 59

3. Median = 30

1, 6, 26, 27, (30),31, 33, 34, 59

4. Q1 = (26+6) ÷ 2 = 16

1, [6, 26], 27, (30), 31, 33, 34, 59

5. Q3 = (33+34) ÷ 2 = 33.5

1, 6, 26, 27, (30), 31, [33, 34], 59

The errors in the box and whisker plot are:

1. The min value was displayed as 0 instead of 1.

2. The first quartile (Q1) was displayed as 10 instead of 16

3. The third Quartile (Q3) was displayed as 35 instead of 33.5

4. The max value was displayed as 60 instead of 59.

8 0
3 years ago
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