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balu736 [363]
3 years ago
8

What is the distance between (1,7) and (9,1)

Mathematics
1 answer:
kotegsom [21]3 years ago
6 0

Answer:

10

Step-by-step explanation:

Given two points we can use the distance formula to calculate the distance between the two points.

Formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Where the x and y values are derived from the given points.

we are given the points (1,7) and (9,1)

To find the distance we plug in the x and y values of the points into the formula

d=\sqrt{(9-1)^2+(1-7)^2} \\9-1=8\\1-7=-6\\d=\sqrt{8^2+(-6)^2} \\8^2=64\\-6^2=36\\d=\sqrt{64+36} \\64+36=100\\\sqrt{100} =10\\d=10

So we can conclude that the distance between the points (1,7) and (9,1) is 10 units

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<img src="https://tex.z-dn.net/?f=%20%7B%20%5Ccos%5E%7B4%7D%5Calpha%7D%20%5C%3A%20%2B%20%20%20%5Csin%5E%7B2%7D%20%5Calpha%20%5C%
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Proved

Step-by-step explanation:

cos^4\alpha +sin^4\alpha =\frac{1}{4}(3+cos4\alpha )\\\\

Take the Left Hand Side:

cos^4\alpha +sin^4\alpha\\\\(cos^2\alpha )^2+(sin^2\alpha )^2\\\\(\frac{1+cos2\alpha }{2})^2+(\frac{1-cos2\alpha }{2})^2  \\\\\frac{1+2cos2\alpha +cos^22\alpha }{4}+\frac{1-2cos2\alpha +cos^22\alpha }{4} \\\\

\frac{1+2cos2\alpha +cos^22\alpha +1-2cos2\alpha +cos^22\alpha }{4} \\\\\frac{2+2cos^22\alpha }{4} \\\\\frac{1+cos^22\alpha }{2} \\\\\frac{1}{2}(1+cos^22\alpha )\\\\

\frac{1}{2}(1+\frac{1+cos4\alpha }{2})

\frac{1}{2}(\frac{2+1+cos4\alpha }{2})\\\\\frac{1}{4}(3+cos4\alpha )\\\\

Hence Proved!

The following identities were used are attached in an image

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