Question

3A%20%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cfrac%7B1%7D%7B4%7D%20%283%20%2B%20%20%5Ccos4%20%5Calpha%20%20%29%20" id="TexFormula1" title=" { \cos^{4}\alpha} \: + \sin^{2} \alpha \: \: = \: \frac{1}{4} (3 + \cos4 \alpha ) " alt=" { \cos^{4}\alpha} \: + \sin^{2} \alpha \: \: = \: \frac{1}{4} (3 + \cos4 \alpha ) " align="absmiddle" class="latex-formula">
Prove::​

Answer 1

Answer:

Proved

Step-by-step explanation:

$cos^4\alpha +sin^4\alpha =\frac{1}{4}(3+cos4\alpha )$

Take the Left Hand Side:

$cos^4\alpha +sin^4\alpha\\\\(cos^2\alpha )^2+(sin^2\alpha )^2\\\\(\frac{1+cos2\alpha }{2})^2+(\frac{1-cos2\alpha }{2})^2 \\\\\frac{1+2cos2\alpha +cos^22\alpha }{4}+\frac{1-2cos2\alpha +cos^22\alpha }{4}$

$\frac{1+2cos2\alpha +cos^22\alpha +1-2cos2\alpha +cos^22\alpha }{4} \\\\\frac{2+2cos^22\alpha }{4} \\\\\frac{1+cos^22\alpha }{2} \\\\\frac{1}{2}(1+cos^22\alpha )$

$\frac{1}{2}(1+\frac{1+cos4\alpha }{2})$

$\frac{1}{2}(\frac{2+1+cos4\alpha }{2})\\\\\frac{1}{4}(3+cos4\alpha )$

Hence Proved!

The following identities were used are attached in an image