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3 years ago

Can you help me please

Mathematics

2 answers:

Ahat [919]3 years ago

7 0

Answer:

split it in half then take that half and split it into 3rds

Step-by-step explanation:

Can i pls have brainliest

baherus [9]3 years ago

7 0

Answer:

Step-by-step explanation:

1/2x1/3=1/6 so its 1/6

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In the inequality "y is less than or equal to 5 and is greater than or equal to -2," the product of the endpoints will be which

Licemer1 [7]

Answer:

Step-by-step explanation:

Inequality "y is less than or equal to 5 and is greater than or equal to -2":

- 2 ≤ y ≤ 5

This is the interval:

y ∈ [- 2, 5]

The endpoints are:

- 2 and 5

Product of the endpoints:

- 2 × 5 = - 10

Answer choices:

(A) odd ⇒ False, - 10 is even
(B) positive ⇒ False, - 10 is not positive
(C) negative ⇒ True
(D) None of the above ⇒ False, option C is correct

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2 years ago

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ABDF is a regular hexagon. What is the measure of angle A?

dolphi86 [110]

$720 \div 6 = 120$

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3 years ago

Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

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2 years ago

How to solve 18 divided by 4464

DedPeter [7]

Answer:

$18 \div 4464$

Step-by-step explanation:

248

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3 years ago

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Lisa and Judy are wrapping gifts for their children. Lisa is making the bows. She has 37 and 1/3 yards of ribbon. If each bow us

trapecia [35]

Answer:

Step-by-step explanation:

32 2/3

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3 years ago