Let say radius is r
<span>its height is h </span>
<span>its lateral area = y </span>
<span>y = 2 pi r h </span>
<span>since the cylinder is inscribed in the sphere </span>
<span>So (2r )^2 + h^2 = 64 </span>
<span>then 4 (r^2) = 64 - h^2 </span>
<span>since y^2 = 4 (pi)^2 r^2 h^2 </span>
<span>then y^2 = (pi)^2 *h^2 * (64 -h^2) </span>
<span>y^2 = 64 (pi)^2 * h^2 - (pi)^2 * h^4 </span>
<span>2 y y' = 128 (pi)^2 * h - 4 (pi)^2 * h^3 </span>
<span>putting y' = 0 </span>
<span>4 (pi)^2 h ( 32 - h^2)=0 </span>
<span>ether h = 0 testing this value (changing of the sign of y' before and after ) y is minimum </span>
<span>or h = 4 sqrt(2) </span>
<span>testing this value (changing of the sign of y' before and after ) y is maximum </span>
<span>So the maximum value of y^2 = (pi)^2 *32 *( 64 - 32) </span>
<span>y^2 = (pi)^2 * (32)^2 </span>
<span>y = 32 (pi) square feet
hope this helps</span>
Answer:
c) 0.6827
Step-by-step explanation:
We have to find P(-1<Z<1) by using z-table
P(-1<Z<1) = P(Z<1) – P(Z<-1)
P(-1<Z<1) = 0.841345 - 0.158655
P(-1<Z<1) = 0.682689
P(-1<Z<1) = 0.6827
Answer:
Step-by-step explanation:
the median for 35 values, you can cross the first one and last one until there is only one value left, with should be the 18ᵗʰ value
the median for 36 values, same thing, but after cross all, there will be 2 values left instead of 1, just find the mean between 2 values.
Answer:
Step-by-step explanation:
It would be A, the first one.
8.01-(2.2+4.67) ->
8.01-(6.87) ->
1.14 is the answer.
